Re: Copy constructors

From:
"David Webber" <dave@musical-dot-demon-dot-co.uk>
Newsgroups:
microsoft.public.vc.language
Date:
Thu, 5 Jul 2007 18:52:52 +0100
Message-ID:
<ex9nLEzvHHA.2004@TK2MSFTNGP06.phx.gbl>
"Doug Harrison [MVP]" <dsh@mvps.org> wrote in message
news:ru9q83dkqtvrte4i49cc2lduonf4lifa43@4ax.com...

On Thu, 5 Jul 2007 18:11:55 +0100, "David Webber"
<dave@musical-dot-demon-dot-co.uk> wrote:

Can someone remind me of the rules by which a default copy constructor is
provided?

I have a peculiar situation: a class for which I want to *forbid* a
copy
constructor of the form

(1) X::X( const X & );

but instead have something similar of the form

(2) X::X( const X&, const Y& );

I could write (1) and make sure it always ASSERTs, but, rather than do
that,
is there any way I can make the compiler throw an error if I inadvertently
try to call such a thing?


Most classes I create include the following:

class X
{
private:

  // Copyguard
  X(const X&);
  void operator=(const X&);
};

Declaring these functions prevents the compiler from supplying default
versions. Declaring them private turns most attempted usage into
compile-time errors. Not defining them guarantees a link-time error if X
itself or a friend tries to use them.


Thanks Doug and David - like all the best answers simple and elegant!

[I must have a religious aversion to even thinking of declaring members and
not implementing them - time to overcome it <g>.]

Dave

--
David Webber
Author of 'Mozart the Music Processor'
http://www.mozart.co.uk
For discussion/support see
http://www.mozart.co.uk/mzusers/mailinglist.htm

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