Re: _int64 to a hex string

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
microsoft.public.vc.language
Date:
Thu, 19 Apr 2007 12:49:23 -0400
Message-ID:
<f086ik$ir8$1@news.datemas.de>
Bob Bins wrote:

Can some one tell me if the below code is correct? I am trying to
convert a _int64 number to a hex string. Boundschecker is reporting an
invalid parameter error . It looks like its working but I am
getting random ntdll.dll exceptions so I am checking everything.

__int64 ID = 0909090900909090;


Shouldn't this be

  __int64 ID = 0909090900909090i64;

?

long maxSize = 500;
char * szMSG = (char *) LocalAlloc(0,maxSize);

StringCbPrintf (szMSG,maxSize,"%llx",ID);


I am not sure what this function does, but I always thought that to
output an i64 value in 'printf' in hex you would need %I64x format.
Should it be the same for all functions that use 'fprintf' formatting
rules? RTFM if you're in doubt.

Error:
"At least one format specifier is illegal char* _Format = 0x1019E208,
argument 4 in _vsnprintf_s_l."

Inner stack call->

iRet = _vsnprintf_s(pszDest, cchDest, cchMax, pszFormat, argList);


V
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