Re: SAX Parser problem

From:

"vahan" <agavelian@gmail.com>

Newsgroups:

comp.lang.java.programmer

Date:

17 Nov 2006 03:47:12 -0800

Message-ID:

<1163764032.551368.316040@e3g2000cwe.googlegroups.com>

In handle class:

         String localName =null;

        public void startElement(String uri, String localName,
                                 String qName, Attributes attributes)
throws
                SAXException {

            this.localName = localName;
            }
        }

        public void endElement(String uri,
                               String localName,
                               String qName) throws SAXException {
            this.localName = null;

        }

        public void characters(char ch[], int start, int length) throws
                SAXException {
            if ("YourTagName".equalsIgnoreCase(localName)) {
                 String desiredContext =new String(ch, start,
length));
            }
        }

Arne Vajh=F8j wrote:

Mize-ze wrote:

Arne Vajh=F8j wrote:

Mize-ze wrote:

I am using SAX to parse an XML file.
I want to get the "characters" of a specific tag (element)

Right now I extend the DefaultHandler and override public void
characters(char[] ch, int start, int length) method. but this event is
raised whenever there is content in a tag.
How can I get a specific charcters from an element using SAX

I don't have access to the qName from this event.

Override:

    public void startElement(
       String namespaceURI,
       String localName,
       String rawName,
       Attributes atts)
       throws SAXException {

Arne

But where will I have access to the "characters"? (not to the atts)

You find the tag with startElement and the text inside with characters.

Arne