Re: Timeout question on a socket thread

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 30 Jul 2009 11:15:57 -0700 (PDT)
Message-ID:
<05c0a3d2-577f-4832-ac89-6a869b48b8e5@z28g2000vbl.googlegroups.com>
On Jul 30, 12:19 pm, RVic <rvinc...@hotmail.com> wrote:

But say I declare something as final, and initialize it to null in the
declaration (so I can access it in y finally block), can I
subsequently assign it
final OutputStream output = null;
    try {
      output = socket.getOutputStream(); //is this legitimate?}fi=

nally{

     output = null; //=

is this legitimate?

No, it is not legitimate. So don't assign 'null' to 'output'.

That makes the lifetime of 'output' exactly that of the instance of
which it's a member.

This is a good thing.

Here's one of several ways to use such a thing:

 public class Foo
 {
   ...
   public void doSomething()
   {
     final OutputStream output;
     try
     {
       output = socket.getOutputStream();
     }
     catch ( IOException exc )
     {
       logger.error( "Cannot open output stream" );
       return;
     }
     Runnable task = new Runnable()
     {
        @Override public void run()
        {
           byte [] inputBuf = new byte [BUFSIZE];
           try
           {
             for ( int bRead;
                   (bRead = inputBuffered.read( inputBuf )) >= 0;
                 )
             {
               output.write( inputBuf. 0, bRead );
             }
           }
           catch ( IOException ioe )
           {
             logger.error( "Cannot write to output" );
           }
        }
     };
     try
     {
       Thread tt = new Thread( task );
       tt.start();
       ...
       tt.join();
     }
     finally
     {
       try
       {
         output.close();
       }
       catch ( IOException ioe )
       {
         logger.error( "Cannot close stream" );
       }
     }
     ...

This is obviously incomplete and untested, but it should give the
idea.

--
Lew

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