Re: My prime counting function

From:
Jack Marsh <drjkaroo56@yahoo.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 10 Aug 2008 22:10:48 -0400
Message-ID:
<HK-dnXvF4cgxAgLVnZ2dnUVZ_ridnZ2d@comcast.com>

Back when I thought that developing a really fast algorithm would
being attention to my work I got a program in Java that would count
prime up to 10^14 in about an hour, with todays computers it'd take
maybe half an hour. It was still way too slow though to compete with
the fastest algorithms known, and after a time I quit that effort.
The program is PrimeCountH.java and is out there in cyberspace
somewhere for those who wish to run it.


I dug around in cyberspace and found PrimeCountH.java at
http://hismath.blogspot.com/2005_03_01_archive.html.
After converting the htlm back into something javac would accept I got
it running. I have to admit I was impressed with the speed. The recent
discussion of primes was terminated with Arne as the winner ( IMHO )
with code that could find pi(Integer.MAX_VALUE) in approximately 30
seconds on my machine ( dual core 3 GHz XP). JSH's code found the same
value is about 0.05 sec. That can also be compared to a sieve of Atkin
code written in C at about 1.3 sec.

Not being able to leave well enough alone I embarked on a quest to
obtain even more speed for JSH's code. And I am finally done. Some
results:
--------------------------------------------------------
pi(1,000,000,000) = 50,847,534 0.031 sec
--------------------------------------------------------
pi(2,147,483,648) = 105,097,565 0.047 sec
--------------------------------------------------------
pi(1,000,000,000,000) = 37,607,912,018 3.188 sec
--------------------------------------------------------
pi(10,000,000,000,000) = 346,065,536,839 23.282 sec
--------------------------------------------------------
pi(100,000,000,000,000) = 3,204,941,750,802 190.125 sec
----------------------------------------------------------
pi(1,000,000,000,000,000) = 29,844,570,422,669 1784.734 sec

The next to last entry is 10^14 in just over 3 minutes. So computer
speeds have progressed far more that JSH suspected. The final entry is
10^15 in less than half an hour. This code automatically detects and
uses multiple cores, so using a quad core machine should yield even
better results.

Here is the code. I have used Andrew Thompson's Text Width Checker to
verify that all lines are 64 characters or less. I have squeezed it
down to about 400 lines, so don't expect it to be pretty.

--%<------- cut here
// from http://hismath.blogspot.com/2005_03_01_archive.html

//Written by James S. Harris. Copyright 2002-2003.
// All rights reserved.

//My suggestion is to write your own version modifying this one.
//Commercial use is not permitted without my written permission.

//Proper attribution might get me some credit for having found
// the prime counting function
//Play with this, share it, *please* mention where you got it.
/**
  *
  * @author S.J. Marsh PhD ( physics ), based on JSH code
  * @version 1.0
  * @date August 2008
  */
import java.text.DecimalFormat;
public class PrimeCountH {
   private int numThreads;
   private int[] primeList;
   private int primeCount;
   private int maxPrime;
   private final long startTime;
   private long[] dS;
   private int[] smallPI;
   private int subLoopSize = 64;
   /**
    *
    * @param args number [true],
    * calculates pi(number),
    * optional argument "true" prints a couple of extra lines
    * If number is missing, pi(2^31-1) is calculated.
    * extra speed can be obtained by using -Xmx declaration
    * java -cp . -Xmx1560m PrimesCountH 100,000,000,000,000
    * yields
    * pi(100,000,000,000,000) = 3,204,941,750,802 in 193.031 sec
    * on a E6850 3 gHz dual core processor running XP
    */
   public static void main(String[] args) {
     long N = Integer.MAX_VALUE; // sjm add default
     boolean printFlag = false;
     if (args.length>0) {
       // sjm: you may optionally enter first argument as
       // 1,000,000,000,000,000 or 1000000000000000
       try {
         args[0] = args[0].replaceAll(",", "");
         N = Long.parseLong(args[0]);
       } catch (NumberFormatException e) {
         if (args[0].equals("true")) {
           printFlag = true;
         } else {
           System.out
               .println("usage: java PrimeCountH number [true]");
           System.exit(1);
         }
       }
     }
     // for jokers who want to enter negatives
     N = Math.abs(N);
     // The program only uses even N so make it even
     if (N>1) { N += N&1; }
     // Put "true" in as your second argument to see more output
     if (args.length>1&&args[1].equals("true")) {
       printFlag = true;
     }
     Runtime rt = Runtime.getRuntime();
     int processors = rt.availableProcessors();
     int numThreads = 2*processors;
     boolean multiCore = processors > 1;

     PrimeCountH p = new PrimeCountH(N, numThreads, printFlag);

     DecimalFormat df = new DecimalFormat("###,###");
     System.out.print("pi("+df.format(N)+") = "
         +df.format(p.pi(N, multiCore)));
     System.out.println(" in "+p.elapsedTime()+" sec");
   }
   public PrimeCountH(long N, int numThreads, boolean printFlag){
     this.numThreads = numThreads;
     dS = new long[numThreads];
     startTime = System.currentTimeMillis();
     if (N>120) {
       int m_max = (int) Math.sqrt(N)+1;
       // Note: build a bigger prime list than necessary
       // It will work with m_max,
       // but a bigger prime list speeds things up
       int multiplier = doSieve(m_max);
       if (printFlag) {
         System.out.println("Sieve Time: "+elapsedTime()+" sec");
         System.out.println("m_max="+multiplier+"*"+m_max);
       }
     }
   }
   private double elapsedTime() {
     return (System.currentTimeMillis()-startTime)/1000.;
   }
   public int doSieve(int m_max) {
     int multiplier = memoryForSpeedMultiplier(m_max);
     m_max = multiplier*m_max;
     Primes p = new Primes(m_max);
     byte[] b = p.findPrimes();
     primeCount = p.countPrimes(b);
     primeList = p.getPrimes(primeCount+1);
     primeList[primeCount] = m_max;
     maxPrime = primeList[primeCount-1];

     // pi(odd) == pi(odd+1), so only store even numbers
     smallPI = new int[(maxPrime+1)/2]; // memory hog
     int s=0;
     for (int i = 0; i<primeCount; i++) {
       for ( ; s<primeList[i]+1; s += 2) { smallPI[s/2] = i; }
     }
     return multiplier;
   }
   int memoryForSpeedMultiplier(int max) {
     Runtime rt = Runtime.getRuntime();
     long maxMemory = rt.maxMemory();
     long possibleInts = (maxMemory/4)*2; // only evens
     long mult = 4*(int) (possibleInts/max)/5;// don't hog it all
     mult = Math.min(mult, max); // don't burn time for small max
     return (int) Math.max(1, Math.min(mult, 32));
   }
   public int pi(int N) {
     N += ((N&1)==0 ? 0 : 1);
     if (N<121) {
       if (N< 9) { return N/2; }
       if (N<25) { return N/2-(N-4)/6; }
       if (N<49) { return N/2-(N-4)/6-(N-16)/10+(N-16)/30; }
       return
           N/2-(N-4)/6-(N-16)/10+(N-16)/30-(N-36)/14+(N-22)/42;
     }
     if (N<maxPrime) { return smallPI[N>>1]; }

     int S = 0;
     int dS = 0;
     int p = 11;
     boolean preTransition = true;
     int m_max = (int) Math.sqrt(N)+1;
     for (int c = 4; p<m_max; c++) {
       int x = N/p;
       x += x&1;
       if (preTransition) {
         if (p<(int) Math.sqrt(x)+1) {
           dS = pi(x, p)-c;
         } else {
           dS = pi(x)-c;
           preTransition = false;
         }
       } else
         dS = pi(x)-c;
       S += dS;
       p = primeList[c+1];
     }
     return N/2-(N-4)/6-(N-16)/10+(N-16)/30-(N-8)/14+(N-22)/42
         +(N-106)/70-(N-106)/210+2-S;
   }

   public int pi(int N, int m_max) {
     int S = 0;
     int dS = 0;
     int p = 11;
     boolean preTransition = true;
     for (int c = 4; p<m_max; c++) {
       int x = N/p;
       x += x&1;
       if (preTransition) {
         if (p<(int) Math.sqrt(x)+1) {
           dS = pi(x, p)-c;
         } else {
           dS = pi(x)-c;
           preTransition = false;
         }
       } else {
         dS = pi(x)-c;
       }
       S += dS;
       p = primeList[c+1];
     }
     return N/2-(N-4)/6-(N-16)/10+(N-16)/30-(N-8)/14+(N-22)/42
         +(N-106)/70-(N-106)/210+2-S;
   }

   public int transition(long N) {
     int p = 11;
     int m_max = (int) Math.sqrt(N)+1;
     for (int c = 4; p<m_max; c++) {
       long y = ((N+p-1)/(2*p))<<1;
       if (p>=(int) Math.sqrt(y)+1) {
         return c;
       }
       p = primeList[c+1];
     }
     return m_max; // this should never be reached
   }

   class OneCore implements Runnable {
     long N;
     int p, c, core, loopMax;
     boolean preTransition;
     OneCore(long N, int c, boolean preTransition, int core,
         int loopMax) {
       this.N = N;
       this.c = c+core*loopMax;
       this.preTransition = preTransition;
       this.core = core;
       this.loopMax = loopMax;
     }
     public void run() {
       dS[core] = 0;
       if (preTransition) {
         for (int i = 0; i<loopMax; i++) {
           int p = primeList[c+i];
           long y = ((N+p-1)/(2*p))<<1;
           dS[core] += pi(y, p)-(c+i);
         }
       } else {
         for (int i = 0; i<loopMax; i++) {
           int p = primeList[c+i];
           long y = ((N+p-1)/(2*p))<<1;
           dS[core] += pi(y, false)-(c+i);
         }
       }
     }
   }

   /**
    *
    * @param N count primes up to N (should be even)
    * @param multiCore if true use mutiple threads
    * @return pi(N) the number of primes less than N
    */
   public long pi(long N, boolean multiCore) {

     if (N<Integer.MAX_VALUE) { return pi((int) N); }

     long S = 0;
     int p = 11;
     int m_max = (int) Math.sqrt(N)+1;
     int trans = transition(N);
     Thread[] t = new Thread[numThreads];
     // preTransition
     for (int c = 4; c<trans;) {
       if (multiCore&&c+(numThreads*subLoopSize)<=trans) {
         for (int i = 0; i<numThreads; i++) {
           t[i] = new Thread(new OneCore(N, c, true, i,
               subLoopSize));
           t[i].start();
         }
         c += numThreads*subLoopSize;
         try {
           for (int i = 0; i<numThreads; i++) {
             t[i].join();
             S += dS[i];
           }
         } catch (InterruptedException e) {
           System.out.println("program interupted");
           System.exit(1);
         }
       } else {
         // original or tidy up end of loop
         p = primeList[c];
         long y = ((N+p-1)/(2*p))<<1;
         S += pi(y, p)-c;
         c++;
       }
     }
     // postTransition
     for (int c = trans; p<m_max;) {
       if (multiCore&&c+numThreads*subLoopSize<primeList.length-1
           &&primeList[c+numThreads*subLoopSize]<m_max) {
         for (int i = 0; i<numThreads; i++) {
           t[i] = new Thread(new OneCore(N, c, false, i,
               subLoopSize));
           t[i].start();
         }
         c += numThreads*subLoopSize;
         try {
           for (int i = 0; i<numThreads; i++) {
             t[i].join();
             S += dS[i];
           }
         } catch (InterruptedException e) {
           System.out.println("program interupted");
           System.exit(1);
         }
       } else {
         p = primeList[c];
         long y = ((N+p-1)/(2*p))<<1;
         long dSx = pi(y, false)-c;
         S += dSx;
         c++;
       }
       p = primeList[c];
     }
     return N/2-(N-4)/6-(N-16)/10+(N-16)/30-(N-8)/14+(N-22)/42
         +(N-106)/70-(N-106)/210+2-S;
   }
   public long pi(long N, int m_max) {
     if (N<Integer.MAX_VALUE) { return pi((int) N, m_max); }
     long S = 0;
     long dS = 0;
     int p = 11;
     boolean preTransition = true;
     for (int c = 4; p<m_max; c++) {
       long y = ((N+p-1)/(2*p))<<1;
       if (preTransition) {
         if (p<(int) Math.sqrt(y)+1) {
           dS = pi(y, p)-c;
         } else {
           dS = pi(y, false)-c;
           preTransition = false;
         }
       } else
         dS = pi(y, false)-c;
       S += dS;
       p = primeList[c+1];
     }
     return N/2-(N-4)/6-(N-16)/10+(N-16)/30-(N-8)/14+(N-22)/42
         +(N-106)/70-(N-106)/210+2-S;
   }

}
/**
  * class to find small ( up to Integer.MAX_VALUE ) primes.
  */
// based on code from Arne Vajh?j in c.l.j.p
class Primes {
   private int size;
   private byte[] b;
   private final static int[] MASK = {
     0x01, 0x02, 0x04, 0x08,0x10, 0x20, 0x40, 0x80 };
   public boolean isPrime(byte[] b, int ix) {
     return (b[ix>>4]&MASK[(ix&0x0F)>>1])==0;
   }
   private void setBit(byte[] b, int ix) {
     b[ix>>4] |= MASK[(ix&0x0F)>>1];
   }
   private static final int[] countMask = new int[256];
   static {
     for (int b = 0; b<256; b++) {
       for (int i = 0; i<8; i++) {
         countMask[b] += ((b>>i)&1)!=0 ? 1 : 0;
       }
     }
   }
   public int countPrimes(byte[] b) {
     int bitCount = 0;
     for (int i = 0; i<b.length; i++)
       { bitCount += countMask[0xff&~b[i]]; }
     return bitCount;
   }
   public byte[] findPrimes() {
     b = new byte[size/16+1];
     // tidy of last few bits beyond size
     for (int i = size; i<16*b.length; i+=2) {setBit(b,i);}
     int sqrtSize = (int) Math.sqrt(size);
     for (int p = 3; p<=sqrtSize; p += 2) {
       if (isPrime(b, p)) {
         for (int j = p*p; j<=size&&j>0; j += (2*p)) {
           setBit(b, j);
         }
       }
     }
     return b;
   }
   public Primes(int size) { this.size = size; }
   public int [] getPrimes(int num) {
     int [] primes = new int[num];
     int ndx = 0;
     primes[ndx++]=2;
     for(int i=3; i<size && ndx<num; i+=2) {
       if( isPrime(b,i) ) {
          primes[ndx++] =i ;
       }
     }
     return primes;
   }
}

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