Re: Java blunders

From:
Eric Sosman <esosman@comcast-dot-net.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 28 Jul 2014 16:39:27 -0400
Message-ID:
<lr6cdv$se9$1@dont-email.me>
On 7/28/2014 4:23 PM, Josip Almasi wrote:

On 07/24/2014 03:53 AM, Roedy Green wrote:

On Wed, 23 Jul 2014 19:55:09 -0400, Arne Vajh?j <arne@vajhoej.dk>
wrote, quoted or indirectly quoted someone who said :

But is it a problem in real world programming?

I have never seen a problem due to this.


The most common error is like this:

out.println ( "the answer is " +
a + b
+ ".");

you must write that as:

out.println ( "the answer is " + (a + b) + ".");


I think you guys missed worst thing with java concatenation, and it's
got nothing to do with operator.
It's about how operator gets interpreted:

out.println ( new StringBuffer("the answer is ").append(new
StringBuffer(a + b)).append(new StringBuffer("."));


     Why do you think this is so? javac 1.8.0_11 compiles it to
the equivalent of

    out.println(new StringBuilder()
        .append("the answer is ")
        .append(a + b)
        .append(".")
        .toString());

.... and I think all javac's have done so for a long time (but I
don't have them available for checking).

It's three new objects, all synchronized.


     ... for suitable values of "three" (i.e., 2) and "all" (0).

OK I haven't read the spec for a while but that's it IIRC, spec requires
it that way.


     StringBuilder replaced StringBuffer for this purpose in Java 1.5,
just under ten years ago. I guess that counts as "a while." ;-)

And if you want to avoid the garbage, you need to

StringBuilder shit = new StringBuilder();
shit.append("the answer is ");
shit.append(a + b);
shit.append(".");
and another line to get the string.


     Um, er, no.

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