Re: Help w/ primitive type byte

From:
=?ISO-8859-1?Q?Arne_Vajh=F8j?= <arne@vajhoej.dk>
Newsgroups:
comp.lang.java.programmer
Date:
Sat, 09 Dec 2006 00:25:46 -0500
Message-ID:
<457a48dc$0$49207$14726298@news.sunsite.dk>
Bryan wrote:

On Dec 8, 7:29 pm, Arne Vajh?j <a...@vajhoej.dk> wrote:

Bryan wrote:

I was wondering if anyone would be willing to help me understand what
is going on with some code that I came across. It has to do with the
primitive type byte. What it's modeling basically is a register in a
device such as a remote terminal unit (RTU). The register holds a word
(byte[2]). Can someone explain what is going on with the code below?
  private byte[] m_Register = new byte[2];
  public final synchronized void setValue(int v) {
    m_Register[0] = (byte) (0xff & (v >> 8));
    m_Register[1] = (byte) (0xff & v);
  }
  public final int toInteger() {
    return ((m_Register[0] & 0xff) << 8 | (m_Register[1] & 0xff));
  }Does the code not work as it should ?

Or are you looking for an explanation of the operators used ?

The code works fine. I'm looking for an explanation of how it works.


& is binary and
| is binary or
 >> is bit shift down
<< is bit shift up

Try and do the calculations in binary radix on a piece of paper.

It is not that difficult.

Arne

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