Re: Data Validation

From:
Eric Sosman <Eric.Sosman@sun.com>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 29 Jan 2007 18:01:53 -0500
Message-ID:
<1170111714.141901@news1nwk>
BlackJackal wrote On 01/29/07 17:44,:

I am really new to programming so take it easy on me :)

Here is the code. Basically what I want it to do is whenever the user
enters in 1 2 or 3 to say good job. When the user enters 4 to quit
and anything else display an error message. This code works fine as
long as the user enters in a int if anything else is entered it
crashes. How can i fix this? Thanks

   import javax.swing.*;
    public class Input123
   {
       public static void main(String[] args)
      {
         String input;
         int selection = 0;
         while (selection != 4) {
            input = JOptionPane.showInputDialog(null,"Enter in either
1, 2, 3, or 4 to quit");
            selection = Integer.parseInt(input);
            if(selection == 1 || selection == 2 || selection == 3) {
               JOptionPane.showMessageDialog(null,"Good Job");
            }
            else if(selection == 4){
               System.exit(0);
            }
            else {
               JOptionPane.showMessageDialog(null,"You have entered an
invalid character, Please try again.");
            }

         }

         System.exit(0);
      }
   }


    If the user enters junk, Integer.parseInt() will throw
NumberFormatException. If you want to keep going after the
exception is thrown, you must catch it and deal with it.
Here's one way:

    while (true) { // selection != 4 is useless
        input = ...;
        try {
            selection = Integer.parseInt(input);
        }
        catch (NumberFormatException ex) {
            selection = 0;
        }
        if (... as above ...)
    }

--
Eric.Sosman@sun.com

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