Re: JTable - Display Boolean as Check Box - Problem Setting Background colour

The DefaultTableCellRenderer simply extends JLabel, so by just
extending that one it will be hard to get to a checkbox.

Following class, taken from the JTable code and adapted to what you
want, could do the work for you:

class BooleanRenderer extends JCheckBox implements TableCellRenderer {
   private static final Border noFocusBorder = new EmptyBorder(1, 1,
1, 1);

   public BooleanRenderer() {
       super();
       setHorizontalAlignment(JLabel.CENTER);
       setBorderPainted(true);
   }

   public Component getTableCellRendererComponent(JTable table,
                                                  Object value,
                                                  boolean isSelected,
                                                  boolean hasFocus,
                                                  int row,
                                                  int column) {
       boolean val = (value != null &&
((Boolean)value).booleanValue());

       if (isSelected) {
           setForeground(table.getSelectionForeground());
           super.setBackground(table.getSelectionBackground());
       } else {
           setForeground(table.getForeground());
           if (val) {
               cell.setBackground(Color.cyan);
           } else {
               setBackground(table.getBackground());
           }
       }
       setSelected(val);

       if (hasFocus) {

setBorder(UIManager.getBorder("Table.focusCellHighlightBorder"));
       } else {
           setBorder(noFocusBorder);
       }

       return this;
   }
}

Regards,

Bart