Re: Writing an int to a socket

From:
Nigel Wade <nmw@ion.le.ac.uk>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 2 Oct 2009 09:29:30 +0000 (UTC)
Message-ID:
<ha4h5q$i73$2@south.jnrs.ja.net>
On Thu, 01 Oct 2009 15:48:15 +0100, Mark wrote:

Hi,

I have the following code which I want to write a 32 bit integer to a
socket (Network byte ordering). For example:

    int value = 11;
    ByteBuffer buf = ByteBuffer.allocate(4);
    buf.order(ByteOrder.BIG_ENDIAN);
    buf.putInt(value);
    buf.flip();
    _channel.write(buf);

(_channel is a SocketChannel)

However the receiver does not see the correct data. It receives (hex) :
30 31 30 2C

Can anyone tell me how to correct this? TIA.


Java IO is in network byte order by default. You only need to worry about
endian issues when reading/writing little endian data.

Personally, I would use a Socket, get its output stream and wrap it in a
DataOutputStream then use the DataOutputStream.writeInt(int) method. Do
you have some underlying reason for using ByteBuffer and nio?

But, that apart, I can't actually see anything wrong with the above code.
Perhaps the problem lies in the code you are not showing us, including
the code which claims to read this data.

--
Nigel Wade

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