Re: Exec() problems on Windows
MMilkin@gmail.com wrote:
Im trying to automate some setupstuff
However im having problems doing this on Windows It seems that the file
gets entered and the first while loop returns all the errors that could
popup. However the second loop is not returning any output that is
occuring and the program is stalling.
proc = rt.exec("Blah.bat");
stderr = proc.getErrorStream();
isr = new InputStreamReader(stderr);
br = new BufferedReader(isr);
iostr = proc.getInputStream();
ist = new InputStreamReader(iostr);
bri = new BufferedReader(ist);
while ( (line = br.readLine()) != null)
{
myString = line;
System.out.println("Error:" + line + ":Error");
}
line = null;
while ( (line = bri.readLine()) != null)
{
myString = line;
System.out.println("Error:" + line + ":Error");
}
System.out.println("waiting for proc");
exitVal = proc.waitFor();
if(exitVal > 0)
{
System.out.println("exitVal: " + exitVal);
}
The problem you are running into is the normal catch22 situation with Process
and reading the stdout/stderr streams. You are reading the error stream until
it closes (i.e. the process completes), then you read the output stream. If the
output stream fills the buffer and blocks the process, the process won't exit
so the first while loop won't terminate. If you reverse the order in which you
read the streams it doesn't solve the problem, it only reverses the failure
mode.
What you need to do is read both streams in parallel, and this normally requires
at least 2 threads. Which thread reads which stream, and what the thread does
with the data, is totally dependent on the expected data and how it needs to be
processed.
--
Nigel Wade, System Administrator, Space Plasma Physics Group,
University of Leicester, Leicester, LE1 7RH, UK
E-mail : nmw@ion.le.ac.uk
Phone : +44 (0)116 2523548, Fax : +44 (0)116 2523555