Re: convenient way to read text file multiple times without reopening it

From:
Zig <none@nowhere.net>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 14 Nov 2007 22:18:53 -0500
Message-ID:
<op.t1tctrqr8a3zjl@mallow.earthlink.net>

Without locking this will not work (at least not on Unix-like systems)=

  =

and if
write lock does not restrain from file removal (which is write access =

to

directory, not the file), then even lock will not help.
Imagine this scenario:
- my program opens the file
- somebody else renames or removes the file (the file will disappear f=

rom

  directory, but it's open file descriptors still work)
- optionally: another file with the same name is created
- I try to open the file with filename again, but either it does not =

exist or
  is another file


I have a vague memory in Windows that when you force deletion of an open=
  =

file, it will invalidate the file descriptors. Thus even if you have a =

stream created, reads after the point of deletion will throw an =

IOException.

If you really need to be able to reproduce a read, you might consider =

using File.createTempFile, copy the source to the temp, and then just =

re-read from temp file, since the probability of other apps mucking with=
  =

temp files might be somewhat lower.

It may also be possible (I haven't tried this but it's a fairly easy =

 =

test)
to open your file as a FileInputStream, get the stream's FileChannel =

and

then reset the position of that channel.


I just tried it and it works when I am reading from that FileInputStre=

am,

but not when I create InputStreamReader from that FileInputStream.
Here is my code:

    public static void main(String[] args) throws IOException{
        FileInputStream is = new FileInputStream("input");
        FileChannel fc = is.getChannel();
        InputStreamReader reader = new InputStreamReader(is);
        for(int j=0;j<2;++j){
            for(int i=0; i<5; ++i){
                int x = is.read(); /* (X) */
                if(x==-1)
                    System.exit(1);
                System.out.print((char) x);
            }
            fc.position(0);
        }
    }

File "input" contains text "0123456789".
When I run this program, it outputs
"0123401234" as expected.

But when I change the line marked with /* (X) */ to
    int x = reader.read();
then I get this output:
"0123456789", so the fc.position(0) had no effect.

Maybe there is some buffering in InputStreamReader,
but that I would expect only from BufferedReader.


Think of InputStreamReader as a bridge from byte[] to char[]. =

BufferedReader provides the decoded char buffer (char[]), but the =

InputStreamReader is still responsible for the binary reading, and thus =
it =

does maintain it's own private byte[] buffer.

When it comes to streams, once you wrap one stream with another stream, =
 =

any further direct changes to the underling stream (without going throug=
h =

the outer stream first) usually result in "undefined" behavior of the =

outer stream. Thus, it's usually best to avoid making such changes.

For your case, if you are using NIO, you can use CharsetDecoder. You =

should be able to create your own ByteBuffer and CharBuffer, and use =

FileChannel.position + CharsetDecoder.reset to reset yourself back to a =
 =

state. Alternatively, you might use =

java.nio.channels.Channels.newReader( <your FileChannel>, <your =

CharsetDecoder> ): just use the postion + reset on the channel + decoder=
  =

and throw away the Reader without closing it - eventually closing the =

channel when you are done.

HTH,

-Zig

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