Re: I have doubt
On Aug 14, 7:38 am, Manju <manjiri...@gmail.com> wrote:
hii
thanks for reply. I perfectly agree with u but when I think about
memory allocation of this expression I am not able to analyze it.
Could u explain that??
Best Regards
Manjiri (Manju)
On Aug 14, 2:34 pm, "LewyG" <lewynewsgr...@gazeta.pl> wrote:
"Manju" <manjiri...@gmail.com> wrote in message
news:1187082187.867372.205060@z24g2000prh.googlegroups.com...
int x=2;
int y;
y=x++*++x;
For this output is 8
I would like to know how this internally works
y = 2 [3] * [4] 4;
y = 2*4 = 8;
in [] is value after incrementation to show how this goes.
Sometimes the best thing to do is show rather than tell.
/cygdrive/d/dl# cat TestPP.java
public class TestPP
{
public static void main(String[] args)
{
int x = 2;
int y = x++ * ++x;
System.out.println(y);
}
}
/cygdrive/d/dl# javac TestPP.java
/cygdrive/d/dl# java -cp . TestPP
8
/cygdrive/d/dl# javap -c -classpath . TestPP
Compiled from "TestPP.java"
public class TestPP extends java.lang.Object{
public TestPP();
Code:
0: aload_0
1: invokespecial #1; //Method java/lang/Object."<init>":()V
4: return
public static void main(java.lang.String[]);
Code:
0: iconst_2
1: istore_1
2: iload_1
3: iinc 1, 1
6: iinc 1, 1
9: iload_1
10: imul
11: istore_2
12: getstatic #2; //Field java/lang/System.out:Ljava/io/
PrintStream;
15: iload_2
16: invokevirtual #3; //Method java/io/PrintStream.println:(I)V
19: return
}
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