Re: Do you know how Java read character value greater than 128/255?

From:
Lew <lew@nowhere.com>
Newsgroups:
comp.lang.java.help,comp.lang.java.programmer
Date:
Wed, 13 Dec 2006 11:11:15 -0500
Message-ID:
<ZPKdnWCB3by5ux3YnZ2dnUVZ_qqrnZ2d@comcast.com>
RC wrote:

int c;
while ((c = bufferedReader.read()) > -1 ) {
              if (c > (int)128) {


128 is already an int, so casting it to int has no effect.

                  System.err.println(
                                   (char)c + " " +
                                   c + " " +
                                   Integer.toOctalString(c) + " " +
                                   Integer.toHexString(c)
                                   );
              }
}
bufferedReader.close();

This is fine, I got print all characters which ASCII value greater than
128.

Now I do the same in C

if ((fp = fopen("inputfile_name", "r")) == NULL) {
        fprintf(stderr, "Can't open %s\n", argv[1]);
        exit(2);
}
int c;
while ((c = getc(fp)) != EOF) {


The C function getc() returns a byte-scale value, not a 16-bit value as does Java.

       if (c > 128) {
           printf("%c %d %o %x\n", c, c, c, c);
       }
}
fclose(fp);

But in C I don't get print any character ASCII value greater than 128 by
read the same file.
I just wonder why, how do Java read those character ASCII greater
than 128?


Java is likely not reading ASCII but UTF-8. Have you tried the Java program
with the InputStreamReader encoding set to "US-ASCII"?

For a fuller answer one would need to know the contents of the file.

Check out the API docs for java.io.InputStreamReader and java.nio.charset.Charset.

- Lew

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