Re: Regex doesn't recognize single quote

From:
Roedy Green <see_website@mindprod.com.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Sat, 07 Jan 2012 14:41:38 -0800
Message-ID:
<tphhg71jbmq4q2vj5dtno5r01igvgdavh2@4ax.com>
On 7 Jan 2012 11:42:26 GMT, ram@zedat.fu-berlin.de (Stefan Ram) wrote,
quoted or indirectly quoted someone who said :

That is not what a regex is for.


 How do you know what it is for?


Regexes are for searching for patterns. Transforming or deleting
characters is much simpler done with a for loop.

How do I know what a regex is for? I am familiar with the API. I have
attempted to use them for various purposes and discovered they were
suitable for some and not for others.

Just use a StringBuilder the length of your String. Then
loop through the chars with charAt. If the character is a
' or \w, ignore it, else append. If it gets complex, use a
switch or if it gets really complicated use a BitSet.


 This might be needless (as far as we know right now)
 optimization bloating the code reducing its readability and
 low-level thinking, which might be required sometimes, but
 does not serve as a general rule. Still it is nice to know
 how it could be done if required.


What is your simpler implementation?

/** remove ' and \w from string
  * @param s string to process
  * @return string without ' or \w
  */
private static String scrunch( final String s )
{
final Stringbuilder sb = new StringBuilder( s.length() );
for (int i=0; i<s.length(); i++ )
  {
  char c = s.charAt(i);
  if ( !( c = '\'' || c = '\w' ) )
     {
     sb.append ( c );
     }
  }
return sb.toString();
}
--
Roedy Green Canadian Mind Products
http://mindprod.com
If you can't remember the name of some method,
consider changing it to something you can remember.
 

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