mysql callable statement problem

From:
"lightning" <huang.lightning@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
10 Feb 2007 22:15:23 -0800
Message-ID:
<1171174523.821893.98090@q2g2000cwa.googlegroups.com>
my Mysql is 5.0.18

In database "test" I created a procedure:

mysql> delimiter //
mysql> create procedure demoSp(IN inputParam VARCHAR(255),INOUT
inOutParam INT)
    -> begin
    -> declare z INT;
    -> set z=inOutParam + 1;
    -> set inOutParam = z;
    -> select inputParam;
    -> select CONCAT('dfjd',inputParam);
    -> end//

just add 1 to the IN/OUT param and select some stuff.
In fact this code is from the Mysql connector/J 's doc

In java code I wrote:

CallableStatement cStmt = con.prepareCall("{call demoSp(?,?)}");
cStmt.registerOutParameter(2, Types.INTEGER);
cStmt.setString("inputParam", "abc");
cStmt.setInt("inOutParam",2);

boolean had = cStmt.execute();
while (had) {
   ResultSet rs = cStmt.getResultSet();
   while (rs.next())
       System.out.println(rs.getString(1));
   had=cStmt.getMoreResults();
}
System.out.println(cStmt.getInt("inOutParam"));
con.close();

-----------------------------------
but the result is an error says "Out of range value adjusted for
column 'inOutParam' at row 1"
so I go on the net and search something says that I can solve this by
edit the my.ini, just remove the "STRICT_TRANS_TABLES" from the sql-
mode option and restart the db server.

I did this ,and the result give me:

abc
dfjdabc
1

no matter how I change the value of the "inOutParam", it just return
"1".

By accident , I just replace the line "

 cStmt.setInt("inOutParam",2);

to

 cStmt.setInt(1,2);

the result changes to be this:

2
dfjd2
3

My default charset is set to UTF-8

my connector/J version is 3.1.0
my jdk version 1.5.0

Is this a bug or did I miss something???

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