Re: Receiver in Outputstream.read() stops after 2735 bytes

From:
Nigel Wade <nmw@ion.le.ac.uk>
Newsgroups:
comp.lang.java.programmer,comp.lang.java.help
Date:
Wed, 6 Jan 2010 09:47:57 +0000 (UTC)
Message-ID:
<hi1m8d$8va$1@south.jnrs.ja.net>
On Tue, 05 Jan 2010 20:06:20 +0100, Bart Friederichs wrote:

Tom Anderson wrote:

On Mon, 4 Jan 2010, Bart Friederichs wrote:

The code is part of a large file copying program. See also
http://blog.friesoft.nl/2009/10/24/sending-really-big-files/


That's called 'scp'


Too complex for a normal user. Not cross platform (or is there a decent
Windows scp implementation?)


WinSCP, if you want all the widgety-clickety bits and pieces.

and doesn't work behind a firewall without
touching that firewall.


Nothing will, or at least nothing should. After all, that's rather the
point of a firewall in the first place.

If the person using the software isn't sufficiently au fait with the
security requirements, and implications, of opening the requisite holes
in their firewall then you have to question whether they should really be
doing that. Using a piece of software which bypasses the firewall,
without understanding what that software does or what the implications of
its actions are, is exceedingly risky. One prime example of this is
Windows - lots of people with no clue of how the Internet works, or how
to secure themselves from attack, relying on a piece of software
(Windows) to handle it all for them. Look how well that's worked out.

--
Nigel Wade

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