Re: TimerTask not work as expected

From:
SamuelXiao <foolsmart2005@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 12 Jan 2011 07:17:18 -0800 (PST)
Message-ID:
<5c859085-f501-42da-b197-a1f157f63d40@v17g2000vbo.googlegroups.com>
On Jan 12, 8:47 pm, Lew <no...@lewscanon.com> wrote:

SamuelXiao wrote:

Hi all, I am writing a simple monopoly board game, there're only 2
tokens, one is controlled by human, another by PC. I am trying to
make it turn based and move around the map step by step. Then when=

 I

use TimerTask to trigger the step-forward movement, it's ok for the
token controlled by human, but for the PC one. It doesn't move as
expected. Below is part of the codes for Dice Roll button& Don=

e

button.

                            timer.schedul=

e(new TimerTask(){

Don't use TAB characters to indent Usenet posts; use spaces (up to four p=

er

level).

                                  =

  private int temp = Dice1 + Dice2;

You have not synchronized access do 'Dice1' (variable names should start =

with

a lower-case letter) or 'Dice2'.

...

how could I make sure that btnRoll() is done then go to the next
code?


Read up on 'volatile', 'synchronized' and other concurrent-programming
constructs in Java. Buy, read and study /Java Concurrency in Practice/=

 by

Brian Goetz, et al.

Any help would be appreciated.

Travers Naran wrote:

Timer runs TimerTask in a _separate_ thread. There are a few ways y=

ou

could synchronize this, but I'd recommend looking at wait()/notify().
Try to remember that you are waiting for your TimerTask to be called
Dice1+Dice2 times before you leave.

SamuelXiao wrote:

Thanks for youjr suggestion, I use wait() now, but it comes to another
problem. I added wait() in the AITurn() method..Then now an exceptio=

n

was caught..

    public void AIturn(int tempNumOfPlayers){
           long temp = (long) (Dice1 + Dice2) * 100;
           btnRoll();
           SystemLogHelper.info("players.get(turn-1): " +
players.get(turn-1).getName());
           SystemLogHelper.info("players.get(turn-1).getPos=

ition(): " +

                           players.get(turn=

-1).getPosition());

           try {
                   this.wait(temp);


Putting 'this.' in front of method calls is useless and misleading.

                   // notify();
                   // Thread.sleep(temp);
           }
           catch(InterruptedException e){}

           if(propertymanager.Properties[players.get(turn-1=

).getPosition()]

[0] == 0){
                   SystemLogHelper.info("enter btnB=

uy()");

                   btnBuy();
           }
           btnDone(tempNumOfPlayers);

           // }
           // if(rolled) btnDone(tempNumOfPlayers);
     }
// IllegalMonitorStateException
java.lang.IllegalMonitorStateException
   at java.lang.Object.wait(Native Method)
   at com.xxx.applet.MonopolyBoard.AIturn(MonopolyBoard.java:822)
   at com.xxx.applet.MonopolyBoard.btnDone(MonopolyBoard.java:485)


That exception is thrown when you call 'wait()' without having a "monitor=

"

(lock) held on the 'this' object. This is clearly stated in the Javado=

cs for

the method. Did you read them?

http://download.oracle.com/javase/6/docs/api/java/lang/Object.html#wa...)
"The current thread must own this object's monitor."

You have to synchronize access to data shared between threads. This is=

 a

rather large topic.

Read up on concurrent programming. Measure twice, cut once.

--
Lew
Ceci n'est pas une pipe.


for dice1 & dice2 both are primitive type. And only AITurn() method
need to wait. May I ask how can I wait until another thread finish?
From my search, it just tells 1 thread call another thread to wait
instead of one thread wait for another thread to finish...

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