Re: Sort Map on Value

From:

Wojtek <nowhere@a.com>

Newsgroups:

comp.lang.java.programmer

Date:

Wed, 26 Aug 2009 07:27:11 -0700

Message-ID:

<mn.d1bf7d98d8b82b4b.70216@a.com>

Lew wrote :

Wojtek wrote:

Ok, so this should work then:

class PersonMapKey implements Comparable<PersonMapKey>
{
private String ivKey;
private String ivName;

PersonMapKey( String key, String name )
{
super();

This idiom puzzles me. Why call 'super()' explicitly? Particularly since
the class extends 'Object'?

Coding fluff. I know that super() is called implicitly, however I
always put it in.

   ivKey = key;
   ivName = name;
}

private String getKey()
{
   return ivKey;
}

private String getName()
{
   return ivName;
}

@Override
public int hashCode()
{
   return ivKey.hashCode();
}

@Override
public boolean equals( Object key )
{
   return ivKey.equals( ((PersonMapKey) key).getKey() );
}

@Override
public int compareTo( PersonMapKey personKey )
{
   return ivName.compareTo( personKey.getName() );
}

Is this consistent with 'equals()'?

No, it is consistent with compareTo() as per the interface.

}
...

--
Wojtek :-)