Re: a simple question realted to StringBuffer

From:
Eric Sosman <esosman@acm-dot-org.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 13 Dec 2006 17:56:39 -0500
Message-ID:
<d-2dnTY4IPe3GB3YnZ2dnUVZ_ternZ2d@comcast.com>
Shawn wrote:

Flo 'Irian' Schaetz wrote:

There's something wrong with your example, but I don't see what...

StringBuffer sb = new StringBuffer(72);
sb.setLength(72);
sb.setCharAt(5, 'A');
System.out.println(sb.toString() + ".");

...works fine for me (1.5). It prints 4 "zero"-chars (squares), an
'A', another 77 zero-chars and a '.'.

Somewhere your example must have a bug :-)

Flo


It is bizarre. Here is my code:
<Java>
public class Test
{
    public static void main(String[] args)
    {
        StringBuffer line = new StringBuffer(72);
        line.setLength(72);
        line.setCharAt(5, 'A');
        System.out.println("line = " + line.toString());
        System.out.println("line = " + line.toString() +".");
        System.out.println("Char at 5 = " + line.charAt(5));
    }
}
</Java>

Here is the output:
line =
line =
Char at 5 = A

I am using Eclipse Java 1.5.


     A hunch: Do you get the same result when you run the
program stand-alone, without Eclipse?

    java your.package.name.here.Test

     It is possible that Eclipse is doing something peculiar
with output lines containing '\u0000' characters -- for
example, treating the '\u0000' as a string terminator, a la C.

--
Eric Sosman
esosman@acm-dot-org.invalid

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