Re: Regular expression pattern for matching end of a URL

From:
"phillip.s.powell@gmail.com" <phillip.s.powell@gmail.com>
Newsgroups:
comp.lang.java.help
Date:
Tue, 24 Jun 2008 07:27:28 -0700 (PDT)
Message-ID:
<64e2163e-2a75-42ce-a93a-fc5538215d0f@c65g2000hsa.googlegroups.com>
On Jun 20, 3:57 pm, Mark Space <marksp...@sbc.global.net> wrote:

phillip.s.pow...@gmail.com wrote:

I am working on a simple method that will assign a specific extension
(e.g. ".jsp", ".php", ".cfm", etc.) to the end of a URL if it doesn't
find anything marking a valid extension, however, I do not want to add
an extension if one is found.


You might try the URI class. Make a URI, get the path, and then just
check that one string for a valid extension. This will be much easier
than trying to parse a URI yourself.


Going forward that is perhaps a really good idea for checking the
validity of a URL, however, what i was trying to do was to check to
see if the URL had an extension and add ".jsp" if it did, otherwise,
add nothing.

What I wound up doing, though, was a lot simpler, by chopping off any
optional query strings and anchors I then checked the newly-created
end of the URL for an extension via Pattern.matches("xxx") and added
".jsp" accordingly.

But the URI class looks interesting as does the URL class. Thanks!

package uritest;

import java.net.URI;
import java.net.URISyntaxException;

public class Main {

     /**
      * @param args the command line arguments
      */
     public static void main(String[] args) throws URISyntaxExcepti=

on {

         // TODO code application logic here

         URI uri = new URI( "http://www.blah.com/registration=

/" );

         String path = uri.getPath();
         if( path.endsWith("/") )
             path = path.substring( 0, path.length()-1 );
         if( !path.matches( ".+\\..*") )
             path += ".jsp";
         System.out.println( path );
     }

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