Re: Declaring members for Interfaces
Wojtek wrote:
Todd wrote :
public enum NonOrdinal
{
RADIUS( 21 ),
DIAMETER( 42 );
private double value;
private NonOrdinal( double value )
{
this.value = value;
}
public double getValue()
{
return value;
}
public NonOrdinal getNonOrdinal(double value) throws
EnumNotFoundException
{
for (NonOrdinal ord : NonOrdinal.values())
if ( ord.getValue == value )
return ord;
throw new EnumNotFoundException("NonOrdinal not found: " + value);
}
}
Is how I do it, though I tend to use an int for my "value" for
persistance. You will need to create your own EnumNotFoundException.
Um, don't get confused with the NonOrdinal.values() as the values()
returned are NOT your private value attribute.
public enum Test {
A1(1),
A2(2);
private static final Map<Integer, Test> byValue;
static {
byValue = new HashMap<Integer, Test>();
for (Test t : Test.values()) {
byValue.put(t.value, t);
}
}
public static Test getByValue(Integer value) {
return byValue.get(value);
}
private Test(Integer value) {
this.value = value;
}
private final Integer value;
public Integer getValue() {
return value;
}
}
Regards,
Leonard
--
Simplicity is the ultimate sophistication.
-- Leonardo da Vinci