Re: Grabbing the integer out from a string...

From:
Jussi Piitulainen <jpiitula@ling.helsinki.fi>
Newsgroups:
comp.lang.java.programmer
Date:
07 Aug 2008 16:17:21 +0300
Message-ID:
<qot1w11dkwu.fsf@ruuvi.it.helsinki.fi>
Danger_Duck writes:

from code that always comes in a predictable form like "function f1
occurred 5 times 100% of blocks executed"

So, as I read line by line of basically the same thing over and over
again (with the two numbers and function name changing), I naturally
wanted to know if there was an easy way to pick out the integers or
split it up at the first int if 2 or more numbers in a string would
make things confusing.


import java.util.regex.Pattern;
import java.util.regex.Matcher;
class M {
    public static void main(String [] args) {
    Pattern p
        = Pattern.compile("function (\\w+)"
                  + " occurred (\\d+) times"
                  + " (\\d+)% of blocks executed");
    for (int k = 0 ; k < args.length ; ++ k) {
        Matcher m = p.matcher(args[k]);
        if (m.matches()) {
        System.out.println("group 1 == |" + m.group(1) + "|");
        System.out.println("group 2 == |" + m.group(2) + "|");
        System.out.println("group 3 == |" + m.group(3) + "|");
        }
    }
    }
}

$ java -cp . M "function foo03_1 occurred 704 times 39% of blocks executed"
group 1 == |foo03_1|
group 2 == |704|
group 3 == |39|

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