Re: Java Arrays.sort throws exception

From:

captain <madison223@gmail.com>

Newsgroups:

comp.lang.java.programmer

Date:

Wed, 14 May 2008 11:32:07 -0700 (PDT)

Message-ID:

<41e9ba61-613c-4b9d-b1b4-3d0b89a8ad7e@8g2000hse.googlegroups.com>

Roedy,

Thank you very much for your response.

My code:

  List adminItems = new ArrayList();

  loop:
     adminItems.add(administeredItem);

  Collections.sort(adminItems);

------------
Collections.class (Sun Code):

   public static void sort(List list) {
    Object a[] = list.toArray();
    Arrays.sort(a); // THROWS EXCEPTION
    ListIterator i = list.listIterator();
    for (int j=0; j<a.length; j++) {
        i.next();
        i.set(a[j]);
    }
    }

Thanks,

Fred

On May 14, 11:15 am, Roedy Green <see_webs...@mindprod.com.invalid>
wrote:

On Wed, 14 May 2008 07:37:00 -0700 (PDT), captain
<bdvolta...@yahoo.com> wrote, quoted or indirectly quoted someone who
said :

When the number of elements gets above around 2700 the Arrays.sort
inside the Collections.sort throws an exception:

java.lang.ArrayIndexOutOfBoundsException

We will have to see your code. In the meantime have a look athttp://min=

dprod.com/jgloss/sort.html

to learn how to write sorts.

Presumably your Comparator is doing some indexing which is failing.
Look carefully at the stack trace for the precise line that is
failing.

--

Roedy Green Canadian Mind Products
The Java Glossaryhttp://mindprod.com