Re: For each and remove

On Fri, 08 Jun 2007 15:58:37 -0700, grasp06110 <grasp06110@yahoo.com>
wrote, quoted or indirectly quoted someone who said :


Your technique would skip processing the element after any removed
element.

here is the new entry in the Java Cheat Sheet

// I T E R A T O R - R E M O V E:
// efficiently removing elements from a List
// (ArrayList, LinkedList etc .
// or Collection.
// You can't remove elements with a for:each.
// This works faster than a get/remove.
// This approach avoids the effects of the List
// renumbering as you go which can cause you to
// inadvertently skip elements or run off the end.
for ( Iterator<Item> iter = Items.iterator(); iter.hasNext(); )
   {
   Item item = iter.next();
   if ( item.isUnwanted() )
       {
       // remove from underlying Collection
       iter.remove();
       }
    }

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