Re: Casting an object in equals Java 5

From:
RedGrittyBrick <RedGrittyBrick@spamweary.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Tue, 30 Sep 2008 10:19:09 +0100
Message-ID:
<48e1ef10$0$2926$fa0fcedb@news.zen.co.uk>
crazzybugger wrote:

On Sep 30, 1:25 pm, Sabine Dinis Blochberger <no.s...@here.invalid>
wrote:

crazzybugger wrote:

Hi,
      I am stuck with a compiler warning while trying to cast an
object inside equals method.
Consider class A<I>{ }
inside this class, I am trying to override equals method. However, I
am not able to cast the received object into the proper type without
compiler warning.
Consider this implementation of equals
public boolean equals(Object that){
     if(that instanceof A){
         A<I> that1 = this.getClass().cast(that); // here I am
getting compiler warning.
        // perform comparisons...
    }
}
what is the right way to cast here ?
thank you...

Since you already test if "that" is an instance of "A", do you even need
to cast it (assuming "A" is the class that implements this "equals()")?

A cast only tells the compiler to pretend/handle it as if that this
object is of type X, it does not convert the object in any way.

<http://mindprod.com/jgloss/cast.html>


If I donot cast it as an object of A<I> how can I access the methods &
attributes of A ?


You can't. But I don't understand your "this.getClass().cast(that);"
I'd try

     A<I> that1 = (A<I>) that;
     that1.methodOfA();

By the way, your choice of example variable names confuses me. I'd maybe
have chosen them like this ...

    public boolean equals(Object object) {
        if (object instanceof A) {
            A<I> a = (A<I>) object;
            ...

Besides If I try casting it as object of type 'A'
and not as A<I>, I get the 'not parameterised' warning!!!


Which is as it should be, why would you expect anything else?

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