Re: Protected methods in Object class

From:
ankur <ankur.a.agarwal@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 22 Nov 2007 12:42:03 -0800 (PST)
Message-ID:
<29e2caab-ab04-4940-b565-e898e01313a8@d4g2000prg.googlegroups.com>
On Nov 22, 12:19 pm, "Mike Schilling" <mscottschill...@hotmail.com>
wrote:

ankur wrote:

So I am a Java newbie and have a simple question here:

protected methods of a superclass are inheritable by the subclass. So
how come the protected methods of Object class namely clone and
finalize not inherited by every class by default ie why is overriding
for these methods necessary in the class which wants to use these
methods and not accessed directly.


Partly, because you're misunderstanding what "protected" means. It's
available in a subclass only to object whose type is that subclass.

    class Class1
    {
        void method1(Object o)
        {
            Class1 dup = (Class1)this.clone(); // good
            Object dup2 = o.clone() // will not compile
        }
    }


Mark,

However in the examples below protected method of Superclass is
available in Testclass to object of type Subclass.

public class SuperClass {
    private int j;
    protected void messageinsuper()
    {
        System.out.printf("This is superclass\n");
    }
}

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

public class SubClass extends SuperClass{

        private int g;
        public void messageinsub()

        {
            System.out.printf("This is a subclass\n");
        }

}

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

public class TestClass {

    public static void main(String[] args) {

        SubClass obj = new SubClass();
        obj.messageinsub();
        obj.messageinsuper();
    }

}

Earlier also I was doing the same thing. Sample extends Object and
TestSample declares an object of type Sample and tries to access
protected method Clone.

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