Re: How to extends a class at runtime?

From:
alex <yalexfan@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 18 Nov 2007 17:37:31 -0800 (PST)
Message-ID:
<0a621fb0-5357-480f-a2a9-db6f83893f29@s8g2000prg.googlegroups.com>
On Nov 19, 12:38 am, Lew <l...@lewscanon.com> wrote:

alex wrote:

I don't know whether the subject is proper, sorry for any confusion.

Now, I have a class A, which is not controlled myself and I can only
get an instance of it at runtime. However, I want to do some adapter
work to it, such as altering its interface.
My solution is using the instance of A as a constructor parameter of a
new adapter class B, for example:

class B {
private A a;
public B(A aa) {
 a = aa;
}
/* adapter stuff here ... */
}

Of course, it works. But I am now wondering whether there is a
solution using inheritance instead of composition? Is there any
pattern or trick?


Most of the time you're going to be better off composing a wrapper class than
extending the target class. This is true even when you control the source.

As an example, consider Collections.unmodifiableCollection( Collection <?
extends T> c). It works by extending the Collection interface, but by
wrapping the target object rather than trying to dynamically extend the target
object's actual class. This has a host of advantages - the resulting
collection need not try to handle, say, List-specific methods even though
object c might be a List, and of course, it's a lot faster, shorter and safer
than trying to dynamically re-extend the class of 'c'.

So even if you are extending, you can also compose. You can extend, in your
example, class or interface A with B, but still compose around an instance of
A internally. That way you aren't dynamically creating classes but have one
created the usual way, with source code and all that.

--
Lew


Thanks, this is a valuable suggestion. I'll look into
unmodifiableCollection now.

--
alex

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