Re: enforce override of method

From:
Zig <none@nowhere.net>
Newsgroups:
comp.lang.java.programmer
Date:
Tue, 26 Jun 2007 01:14:53 GMT
Message-ID:
<op.tuh8e4ls8a3zjl@mallow.earthlink.net>
Just forgot the more obvious, if you are willing to make A abstract, you=
  =

can also make it a factory with an anonymous implementation

public abstract class A implements I {
    protected A() {
    }
    public static A createDefaultA() {
        return new A() {
            public void foo() {
                //default foo
            }};
    }
}

Now, subclass B must implement foo, but users can still get a reasonable=
  =

default implementation (not elsewhere exposed or inheritable).

On Mon, 25 Jun 2007 20:56:54 -0400, Zig <none@nowhere.net> wrote:

Inheritence can't give you what you are looking for, but if you consid=

er =

delegation, you might get the desired effect.

eg:

public class A implements I {
    private final I _delegate;
    protected A(I imp) {
        if (imp==null) throw new NullPointerException();
        _delegate=imp;
    }
    public void foo() {
        _delegate.foo();
    }
    public static A createDefaultA() {
        return new A(new I() {
            public void foo() {
                // default foo method
            });
    }
}

On Mon, 25 Jun 2007 20:12:57 -0400, Mize-ze <zahy.bnaya@gmail.com> wro=

te:

On Jun 26, 2:39 am, "Matt Humphrey" <m...@ivizNOSPAM.com> wrote:

"Mize-ze" <zahy.bn...@gmail.com> wrote in message

news:1182806954.734906.69320@n2g2000hse.googlegroups.com...
| Hi,
| Let's say I have a class A which implements interface I, which has=

 a

| method foo() in it,
| I want (and I must) implement I.foo() method in class A.
|
| Now, I have a Class B which extends A and therefore inherits it's
| foo() method. however,
| I don't want class B to use A's implementation of foo() but instea=

d

| implement its own .
| I can easily just override the method by implementing the foo() =

method
| in B.
|
| BUT what if I want to enforce the user to implement foo()?
| Anyway of doing this?
| It's like having class A as abstract class( foo() as abstract). bu=

t =

it
| isn't...

If B must extend A and foo must be accessible outside of the package=

, =

there
is no way to enforce that B.foo() not override or use A.foo(). If =

there
were a way to enforce it, B could always write a method fooAlt () wh=

ich

calls foo() (because foo is accessible) and then let B.foo () =

"override" by
calling fooAlt().

If foo can be restricted to the package, A can give it default =

protection.
n that case B would then not have any access to it, but no code =

outside of
the package could use A.foo either. B.foo would be available, but i=

t =

would
be different from A.foo and would not override it.

Matt Humphrey m...@ivizNOSPAM.comhttp://www.iviz.com/


Hi Matt,
I'm afraid I wasn't that clear,
I want to have a situation where if one of my developers wants to
extend A he HAS to override
foo() and not use A's implementation (although he can trick the syste=

m

by calling it at fooAlt, that's fine by me...)

Bottom line:
I want he's class not to compile until he implements foo().

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