implements Value<T...>

From:
ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups:
comp.lang.java.programmer
Date:
28 Sep 2008 23:59:32 GMT
Message-ID:
<ellipsis-20080929014611@ram.dialup.fu-berlin.de>
  How can I modify the end of line 6 to make the declaration of
  the class ?Value1? being compiled (similar to the declaration of
  the class ?Value0?, which is being compiled)?

interface Value<T> { public void operation(final T t); }

class Value0<T> implements Value<T[]>
{ public void operation( final T[] t ){}; }

class Value1<T> implements Value<T...>
{ public void operation( final T... t ){}; }

/* Main.java:6: > expected
class Value1<T> implements Value<T...>
1 error ^ */

                           ~~

  Ok, the following class declaration now can be compiled:

class Value1<T> implements Value<T[]>
{ public void operation( final T... t ){}; }

  But I still get a warning:

Main.java:6: warning: operation(T...) in Value1 implements operation(T) in Value; overridden method has no '...'
{ public void operation( final T... t ){}; }
              ^
1 warning

  Is there a way to write this in such a way that there will
  not even be a warning message, retaining the declaration
  ?public void operation( final T... t ){};??

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