Re: Vector (was Re: Change character in string)

From:
"Peter Duniho" <NpOeStPeAdM@nnowslpianmk.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sat, 14 Mar 2009 02:01:18 -0700
Message-ID:
<op.uqrx0gwl8jd0ej@macbook-pro.local>
On Fri, 13 Mar 2009 22:32:11 -0700, Lew <noone@lewscanon.com> wrote:

[...]
   public boolean equals(Object o) {
     if (o == this)
       return true;
     if (!(o instanceof List))
         return false;

     ListIterator<E> e1 = listIterator();
     ListIterator e2 = ((List) o).listIterator();
     while(e1.hasNext() && e2.hasNext()) {
         E o1 = e1.next();
         Object o2 = e2.next();
         if (!(o1==null ? o2==null : o1.equals(o2)))
      return false;
     }
     return !(e1.hasNext() || e2.hasNext());
   }


Interesting that they don't bother to check the size() first for equality,
but instead always enumerate at least all of the elements of the shorter
list.

[...]

I'm still not spotting the difference, exactly.

 If I understand Bent's comments correctly:
 Vector: for any given instance, the equals() method itself is
synchronized, and the getter to retrieve each element of the _other_


What getter? This is what I'm missing.


Sorry...Bent will have to provide the specifics, if you can't find the
details yourself. I haven't bothered to look at the source, nor even try
his example. I don't have enough interest myself to spend the time. I
assume you've confirmed it actually deadlocks as he says, so obviously
each thread is trying to take two different locks _somewhere_.

Since I have to guess, I'd guess that the list iterator is what winds up
calling a synchronized getter. Whether that's actually the get() method,
or some equivalent, I couldn't say (though, the get() method being the one
abstract method in AbstractList, it seems like a pretty good bet to me :)
).

Pete

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