Re: My set fails

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 23 Mar 2008 06:37:48 -0400
Message-ID:
<nLydnUx1-rRgr3vanZ2dnUVZ_judnZ2d@comcast.com>
-Rick- wrote:

   public boolean equals(Object o) {
       if (!(o instanceof SetTest))
           return false;
       SetTest s = (SetTest)o;
       if(s.getS1() == this.getS1() && s.getX1() == this.getX1())
           return true;
       else
           return false;


How come you don't just
   return s.getS1() == this.getS1() && s.getX1() == this.getX1();
?

   }

   public static void main(String[] args){
       populate();
       System.out.println("The size of set is: " + set.size());


rossum wrote:

What is set.size()? You have not declared anything called "set" and
you have not defined a method called"size()".


-Rick- wrote:

   static protected Set<SetTest> set = new TreeSet<SetTest>();
}


And that is the reason I excoriate placing member declarations at the bottom.

The standard is to place them before method declarations:
<http://java.sun.com/docs/codeconv/html/CodeConventions.doc2.html#1852>

To the OP: You cause confusion when you deviate from the standard or the few
allowable variations (e.g., the opening brace on its own line indented the
same as its control statement).

--
Lew

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