Re: encrypted javamail MimeMultipart

From:

"eunever32@yahoo.co.uk" <eunever32@yahoo.co.uk>

Newsgroups:

comp.lang.java.programmer

Date:

Sun, 13 Jun 2010 05:31:25 -0700 (PDT)

Message-ID:

<b119a86c-6504-4f8c-966a-40fcdad4ff4e@w12g2000yqj.googlegroups.com>

On Jun 11, 7:22 pm, Martin Gregorie <mar...@address-in-sig.invalid>
wrote:

On Fri, 11 Jun 2010 06:53:14 -0700, euneve...@yahoo.co.uk wrote:

(4) should become:
- create a ByteArrayInputStream from the decrypted byte arra=

y -

    pass that to a MimeMessage constructor.

    At this point you can use the standard MimeMessage and
    MultiPart methods to parse the message and extract its conte=

nt.

Sorry for all the repeats - the NNTP server I use threw a wobbly this
morning and I hadn't realised it was accepting the post *and then*
locking up until just now.

Thanks Martin but maybe you can help me:

As I said I'm new to this Javamail api and am looking for a succinct
way to obtain the attachment

I can do

MimeMessage msg = new MimeMessage(session, new
FileInputStream("file.txt"));

The resulting msg has three headers which looks right

But when I do
if (msg.getContent() instanceof Multipart) {
saveAttachment

}

True enough: MimeMessage.getContent() can return a lot of things
including InputStreams - thats why it returns an Object!

Did you do what I suggested and download both the JavaMail Design
Specification and the API Documentation? If not, go get them now and read
them. The first example in Design Specification Appendix B shows exactly
how to parse a multipart MIME message.

The Appendix B examples are all available as downloadable source code, so
you can run them and/or swipe useful code from them.

--
martin@ | Martin Gregorie
gregorie. | Essex, UK
org |- Hide quoted text -

- Show quoted text -

Martin

Thanks for your suggestion and I have obtained the Javamail Design
document you describe.
It is very good and I now know about Message, Part, MimePart,
MimeMultipart, MimeMessage and I can see there is an example of how to
read attachments.
I am not at my desk right now so I can't verify it however I am
concerned that if I do the following:

Object content = decryptContent(message, key, publicKey);
And then I try

if (content instanceof MimePart) {
    ...
}
if (content instanceof MimeMultiPart) {
    ...
}
if (content instanceof InputStream) {
    ...
}

And if my code finds itself in "InputStream" then I am back to square
one (?)
And how then do I obtain the attachment which I clearly have

Thanks again to everyone for their suggestions.