Re: Initializing Variables

From:
Pitch <mail@fake.info>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 27 May 2010 11:22:48 +0200
Message-ID:
<MPG.2668584fa03cf203989b57@news.t-com.hr>
In article <alpine.DEB.1.10.1005261957240.16996@urchin.earth.li>,
twic@urchin.earth.li says...

On Wed, 26 May 2010, Gunter Herrmann wrote:

Tom Anderson wrote:

On Tue, 25 May 2010, Arne Vajh?j wrote:

But I would note that in many cases the optimal solution is to
wait declaring the variable until you have a value to give it.


Absolutely. Goes without saying!


There are exceptions to this rule (pun intended)

Foo foo = null;

try {
 foo = new Foo();
 foo.doProcessing();
}
catch (FooException ex) {
 doSomething(ex);
}
finally {
  foo.cleanup();
}

In this case you have to initialize the variable foo.


No, because you should just write it like this:

Foo foo = new Foo();
try {
  foo.doProcessing();
}
catch (FooException ex) {
  doSomething(ex);
}
finally {
  foo.cleanup();
}

If new Foo() can also throw an exception, then wrap that whole lot in a
try-catch or whatever.

tom


If new Foo() throws an exception it's not a problem. If you see this
block as an atomic function "doSomethingFoo()" the caller has to handle
exceptions but the callee has to clean up resources it has allocated.

On the other hand if you DON'T see this as an atomic function - I'd say
it's bad design. :)

--
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