Re: fetch content from google results

From:
prabesh shrestha <prabesh708@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 29 Sep 2008 20:07:49 -0700 (PDT)
Message-ID:
<a5c5639d-3572-4ea7-ba2a-f06584821f1c@y21g2000hsf.googlegroups.com>
package conceptualsearch;

import java.io.*;
import java.net.*;
import java.util.Scanner;

public final class Main {

  public static void main(String... aArgs) throws
MalformedURLException {
      String url="http://en.wikipedia.org/wiki/
Simple_HTML_Ontology_Extensions";
    String urli = "http:'//'www.google.com/search?hl'='en&q'='php";
    String option = "content";
    Main fetcher = new Main(url);
      log( fetcher.getPageContent() );

  }

  public Main( URL aURL ){
    if ( ! HTTP.equals(aURL.getProtocol()) ) {
      throw new IllegalArgumentException("URL is not for HTTP
Protocol: " + aURL);
    }
    fURL = aURL;
  }

  public Main( String aUrlName ) throws MalformedURLException {
    this ( new URL(aUrlName) );
  }

  /** Fetch the HTML content of the page as simple text. */
  public String getPageContent() {
    String result = null;
    URLConnection connection = null;
    try {
      connection = fURL.openConnection();
      Scanner scanner = new Scanner(connection.getInputStream());
      scanner.useDelimiter(END_OF_INPUT);
      result = scanner.next();
    }
    catch ( IOException ex ) {
      log("Cannot open connection to " + fURL.toString());
    }
    return result;
  }

  // PRIVATE //
  private URL fURL;

  private static final String HTTP = "http";
  private static final String HEADER = "header";
  private static final String CONTENT = "content";
  private static final String END_OF_INPUT = "\\Z";
  private static final String NEWLINE =
System.getProperty("line.separator");

  private static void log(Object aObject){
    System.out.println(aObject);
  }
}

here is my code .I could get all the content if i set url as wikipedia
but i could not get the snipplet from google.I don't understant what
is happening.Maybe someone has the solution.

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