Re: Constructor

From:
Lew <noone@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 24 Sep 2008 07:00:03 -0400
Message-ID:
<ee2dnSz2y5wpgEfVnZ2dnUVZ_qednZ2d@comcast.com>
Philipp wrote:

If I write:
<code>
MyClass object = new MyClass(someArgument);
object.doStuff();
</code>

Do I have a guarantee that object is not null when I call doStuff?


Yes.

'new' cannot return 'null'.

Or is there a possible execution path which reaches .doStuf() [sic] with object
being null?


Bo Vance wrote:

No such guarantee.
try {
  MyClass object =
    new MyClass(someArgument);
  object.doStuff();
} catch (someE e) {
  some handling
} // guaranteed object.doStuff() won't be called if
  // new MyClass(someArgument) throws.
See the JLS subsection:
15.9.4 Run-time Evaluation of Class Instance Creation Expressions
<http://java.sun.com/docs/books/jls/third_edition/html/expressions.html#15.9.4>


This doesn't answer the OP's question. That's how the execution might *not*
reach 'doStuff()', but they asked how it might *reach* 'doStuff()' with
'object' not assigned (or assigned 'null').

For that read the JLS on "definite assignment". It gets an entire chapter.
<http://java.sun.com/docs/books/jls/third_edition/html/defAssign.html>

There are ways to reach a reference without it being assigned, basically
involving failure to deal with exceptions.

Foo foo; // I hate including 'Class' or 'object' in identifiers
try
{
   foo = new Foo();
}
catch ( Exception exc )
{
   // completely fail to handle exc
}
foo.doStuff(); // error

--
Lew

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