Re: Declaring members for Interfaces
Wojtek wrote:
Todd wrote :
public enum NonOrdinal
{
RADIUS( 21 ),
DIAMETER( 42 );
private double value;
private NonOrdinal( double value )
{
this.value = value;
}
public double getValue()
{
return value;
}
public NonOrdinal getNonOrdinal(double value) throws
EnumNotFoundException
{
for (NonOrdinal ord : NonOrdinal.values())
if ( ord.getValue == value )
return ord;
throw new EnumNotFoundException("NonOrdinal not found: " + value);
}
OMG! I won't even comment. This is just silly... don't teach people if
you can't solve problems by yourself.
If you really, really need such a mechanism, try this:
public enum Test {
A1( 1 ),
A2( 2 );
private final Integer value;
private static final Map<Integer, Test> byValue;
static {
byValue = new HashMap<Integer,Test>();
for (Test t : Test.values()) {
byValue.put(t.value, t);
}
}
private Test(Integer value) {
this.value = value;
}
private Integer getValue() {
return value;
}
public static Test getByValue(Integer value) {
return byValue.get(value);
}
}
Regards,
Leonard
--
Simplicity is the ultimate sophistication.
-- Leonardo da Vinci