Re: try - catch box

From:

deepak.vaswani@gmail.com

Newsgroups:

comp.lang.java.programmer

Date:

Fri, 4 Jan 2008 01:05:28 -0800 (PST)

Message-ID:

<7f11107b-a924-47d4-a413-81dcb8d822c3@l6g2000prm.googlegroups.com>

On Jan 4, 12:15 pm, "cCss.........." <guptavive...@gmail.com> wrote:

Consider the following code:

try
{
   a=func(); // line-1
   - - - -- - - - - -
   - - - - - - -- - - -}

catch(Exception e)
{
- - - - -}

System.out.println(a); // line-n

In the code func() returns any value to 'a'. If any exception occurs
after line-1. Would line-n print the value of a, or the program will
terminated after catching the exception.

Hi ,

try / catch block is to handle the exception carefully . so if any
exception occurs in try block then it is catch block duty to handle it
properly . and after that everything thing will be perfomed
successfully . provided variable a should be defined and declared
earlier outside the try block properly .

class test
{
    public void test1()
    {
        int s = 0 ;
        try
        {
            s=test2();
            int x=0;
            int z=9;
            int y =z/x;
        }
        catch (Exception e)
        {
            System.out.println(e);
        }
        System.out.println(s);
    }

    public int test2()
    {
        int f=10;
        return f;
    }
    public static void main(String[] args)
    {
        test t = new test();
        t.test1();
        System.out.println("Hello World!");
    }
}