Re: XML traversal in levelorder

From:
"=?ISO-8859-1?Q?C._R=FChl?=" <chris@cruehl.com>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 6 Dec 2007 02:16:25 -0800 (PST)
Message-ID:
<d8b2bfa8-0e50-40f9-9dff-20ef761125a9@s8g2000prg.googlegroups.com>
Okay, I just started over from scratch. I'm parsing the file now into
a DOM and give the XML root node to a method like shown here:

private void visitNodes(Node node)
{
    try
    {
        // child nodes of current node
        NodeList nodeList = node.getChildNodes();

        // loop through child nodes
        for(int i=0; i<nodeList.getLength(); i++)
        {
            if(nodeList.item(i).getLocalName()=="Component")
            {
                System.out.println(nodeList.item(i).getLocalName());
            }
        }
    }
    catch(Exception ex)
    {
        // nothing yet
    }
}

But XML level-order traversal ain't that easy... How and where can I
now insert a recursive call of that method? I can't just put it into
the for-loop, because then I get pre-ordered results. So what should I
do to traverse my file in level-order (breadth-first)?

I hope that someone gives me a little help here. Thanks a lot!

The XML file looks a little like this:

<Component>
   <Component>
      <Component/>
      <Component/>
   </Component>
   <Component/>
</Component>

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