Re: Xml doc = dom.parseString(request.getReader());

From:
 gert <gert.cuykens@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 24 Sep 2007 03:05:23 -0000
Message-ID:
<1190603123.967061.194260@o80g2000hse.googlegroups.com>
On Sep 24, 4:31 am, Daniel Pitts <googlegrou...@coloraura.com> wrote:

On Sep 23, 6:05 pm, gert <gert.cuyk...@gmail.com> wrote:

On Sep 24, 2:46 am, gert <gert.cuyk...@gmail.com> wrote:

I get a java.lang.NullPointerException when i do this ?

try {doc = parser.parse(xmlText);}
catch (SAXException ex){out.println(" <error>"+ex+"</error>\n");}

Debugger or compiler doesn't give me any warnings or anything ?


Why do i always get a 500 response ?

try {doc = parser.parse(new InputSource(in));}
catch (SAXException ex){out.println(" <error>"+ex+"</error>\n");}

deployed with moduleid = www
StandardWrapperValve[query]: PWC1406: Servlet.service() for servlet
query threw exception
java.lang.NullPointerException
        at query.doPost(query.java:37)


What is on line 37 of query.java?

BTW, Class names (and therefor .java files) should always start with a
capitol case letter. "Query" would then be appropriate.

Make sure that "parser" is an actual value, and not just null. You
need to get it from the
DocumentBuilderFactory().newInstance().newDocumentBuilder()


Here is the source code.
http://appwsgi.googlecode.com/svn/trunk/java/query.java
Feel free to give allot of suggestions :)

NullPointerException refers to,
doc = parser.parse(new InputSource(in));

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