Re: Non-Blocking receive on MulticastSocket

From:
"Ryka" <ryka@libero.it>
Newsgroups:
comp.lang.java.help
Date:
Tue, 06 Mar 2007 09:24:36 GMT
Message-ID:
<oraHh.14535$J11.320074@twister1.libero.it>
same problem! receive() is blocking :(
How can I implement a non-blocking receive on a MulticastSocket object?

P.S: Sorry I'm italian and I don't speak English very well...
try{

//join a Multicast group and send the group salutations

String msg = "Hello";

InetAddress group = InetAddress.getByName("228.5.6.7");

try{

MulticastSocket s = new MulticastSocket(6789);

s.joinGroup(group);

DatagramPacket hi = new DatagramPacket(msg.getBytes(), msg.length(),

group, 6789);

s.send(hi);

// get their responses!

byte[] buf = new byte[1000];

DatagramPacket recv = new DatagramPacket(buf, buf.length);

s.receive(recv);

System.out.println(recv.getAddress()+" ");

// OK, I'm done talking - leave the group...

s.leaveGroup(group);

}catch(IOException e2){System.err.println("errore1 "+e2.getMessage());};

}catch(UnknownHostException e){System.err.println("eerore2
"+e.getMessage());};

"Ale" <alkondor@freemail.it> ha scritto nel messaggio
news:1168772094.965383.231590@l53g2000cwa.googlegroups.com...

Hi all!

How can I implement a non-blocking receive on a MulticastSocket object?

With socket objects it was simple:

                       socket = new Socket(hostIP, port);
                       in = new BufferedReader(new
InputStreamReader(socket.getInputStream()));
and so...

                          if (in.ready())
                          {// Receive data}

Thanks.

Ale

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