Re: Why does Java require the throws clause? Good or bad language design?

From:
"Arthur J. O'Dwyer" <ajonospam@andrew.cmu.edu>
Newsgroups:
comp.lang.java.programmer,comp.lang.java.help,comp.lang.misc
Date:
Tue, 20 Feb 2007 13:04:11 -0500 (EST)
Message-ID:
<Pine.LNX.4.61-042.0702201227190.5981@unix36.andrew.cmu.edu>
On Tue, 20 Feb 2007, Michael Rauscher wrote:

Arthur J. O'Dwyer wrote:

On Mon, 19 Feb 2007, Michael Rauscher wrote:

catcher calls higherLevel, so one contract is between catcher and
higherLevel.

higherLevel calls cbf, so there's another contract: between
higherLevel and cbf.


  FWIW, you're wrong. The "contract" is obviously between the main
function 'catcher' and its helper function 'callbackFunc'. Now, I'll
agree that Java does not let us /express/ that contract; but that's
not the same thing as its not existing in the first place.


You can't just ignore the higherLevel method.


   I /want/ to ignore the higherLevel method! Here's an analogy that
I think will be extremely clear to Lisp programmers, but maybe not to
C++/Java programmers: I can write

     for (...) {
        callbackFunc();
     }

instead of

     for (...) throws Exception {
        callbackFunc();
     }

Exceptions thrown by the inner callbackFunc() are quietly and
transparently passed out of the loop and up to the surrounding
context. So why can't I create my own "control structures" by
writing

     ... higherLevel(...) { ... }
     higherLevel(callbackFunc);

instead of

     ... higherLevel(...) throws Exception { ... }
     higherLevel(callbackFunc);

Let's assume a specification that tells us that a value of 42 must not be
passed to callbackFunc. Further, assume there'd be a contract between
callbackFunc and catcher telling catcher.


   Yes, agreed. (Of course, as a C programmer myself, I'd object that
the contract isn't "don't pass me 42", but "if you pass 42 I'll throw
an exception." If the caller broke the contract as you stated it above,
I wouldn't be so nice as to waste my time throwing him an exception. ;)

Now, let's rewrite higherLevel:

void higherLevel( (void)(*cbf)(int), int arr[], int n ) {
   try {
       for ( int i = 0; i < n; i++ )
           cbf(arr[i]);
   } catch ( char *e ) {
   }
}

With this, catcher will never catch an exception.


   Oops!

And now? What's about the contract between catcher and callbackFunc?


   You killed it, that's what happened! So clearly your way of
implementing higherLevel() is at fault. As the name "higherLevel"
implies, to me anyway, higherLevel() should pass exceptions through,
quietly and transparently, up to the surrounding context.

  3. 'catcher' doesn't contain a 'catch' clause, which makes its
name misleading at best. ;)


lol. I'm sorry. I have to concentrate on writing in English, so 3. didn't
came to my mind. I'm happy enough, if my writings don't contain too much of
incorrect English :)

Back to the topic:

catcher needs no catch clause since the contract contains no rule for this.


   Well, I put a 'catch' clause in my original C++ version, which is why
I made a big deal out of it. The Java was supposed to do the same thing
as the C++; that was the whole point!

One may add a catch clause in order to catch unchecked exceptions,
of course.


   Right; and Java's unchecked exceptions do seem to solve the whole
problem.

or if you a checked exception should be thrown,
declare it in CBF#execute's throws-clause.


  That would be nice, but you just said that Java won't allow you to
do that. ("This would lead to a compile-time error ...") Unless of


The example above ("This would lead to a compile-time error") was related to
the throw statement. This time I referred to the throws clause.


   I just tested the code to make sure I wasn't mistaken --- I wasn't.
You get a compile-time error if you say:
(this is a complete translation unit):

interface CBF {
    public void execute(int x);
}

class Foo {
     public void higherLevel( CBF cbf, int arr[] ) {
         for (int i=0; i < arr.length; ++i)
           cbf.execute(arr[i]);
     }

     public void catcher()
     {
         int arr[] = new int[] { 1, 2, 3, 42, 5 };

         CBF callBackFunc = new CBF() {
             public void execute(int x) {
                 if ( x == 42 )
                   throw new Exception();
             }
         };

         try {
             higherLevel( callBackFunc, arr );
         } catch (Exception e) {
             // handle exception somehow
         }
     }
}

Now change it to

         CBF callBackFunc = new CBF() {
             public void execute(int x) throws Exception {
                 if ( x == 42 )
                   throw new Exception();
             }
         };

Still an error; 'execute' doesn't match the interface. Change it to

interface CBF {
    public void execute(int x) throws Exception;
}

Still an error; 'higherLevel' throws an undeclared exception. And now
we're borked, unless of...

...course you propagate the exception specification all the way up into
'higherLevel', which would mean no code reuse in the presence of
checked exceptions.


I don't see anything that would be against code reuse.


   So let's make it

     public void higherLevel( CBF cbf, int arr[] ) throws Exception {
         for (int i=0; i < arr.length; ++i)
           cbf.execute(arr[i]);
     }

Now I see two problems, but one of them might be a mirage. That one
is: what happens if we want to use higherLevel() with a callback
function that might throw something /else/? We'd have to make it

     public void higherLevel( CBF cbf, int arr[] )
             throws Exception, SomethingElse {
         for (int i=0; i < arr.length; ++i)
           cbf.execute(arr[i]);
     }

And then if we want to throw a third thing,

     public void higherLevel( CBF cbf, int arr[] )
             throws Exception, SomethingElse, AThirdThing {
         for (int i=0; i < arr.length; ++i)
           cbf.execute(arr[i]);
     }

Basically, every time our client code changes, we have to go find
our library and patch it. That's not code reuse.
   Now, this "problem" is probably a mirage, because of the coincidence
that in Java, all checked exceptions derive from Exception (am I right?),
so we can just write "throws Exception" and we'll have covered all the
bases.

   The more serious problem is, what happens if catcher2() wants to
perform higherLevel() on callback2(), and this time the contract
between the *2() functions does /not/ involve any exceptions being
thrown?

interface CBF {
    public void execute(int x); // "throws Exception" or not, doesn't matter
}

class Foo2 {
     // This is the same higher-level library function, reused.
     // Pretend it's in a different translation unit.
     public void higherLevel( CBF cbf, int arr[] ) throws Exception {
         for (int i=0; i < arr.length; ++i)
           cbf.execute(arr[i]);
     }

     public void catcher2()
     {
         int arr[] = new int[] { 1, 2, 3, 42, 5 };

         CBF callBack2 = new CBF() {
             public void execute(int x) {
                return; // no exceptions here!
             }
         };

         higherLevel( callBack2, arr );
         // no need for a catch; callBack2 doesn't throw
     }
}

There's no way to make this code work, unless you are willing to do
one of three things:
   (1) Change the library; i.e., give up on code reuse.
   (2) Add spurious "catch" clauses to every use of 'higherLevel',
thus confusing the reader, since exceptions aren't being used in
this code.
   (3) Add spurious "throws Exception" clauses to every function
in the program and a "catch" in main, again confusing the reader,
but at least conserving the vertical space.

   Again I say: AFAICT, if you want C++-ish semantics in Java, you
use unchecked exceptions. There's no magic bullet in either language.
I appreciate your comment crossthread,

Of course, I can't give Java solutions to 'problems' that are not
feasible using Java. So, if the question had been if it's possible to
pass checked exceptions through methods without declaring them, then
I'd answered: no ;)


Truce? ;)

-Arthur

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