Re: Using an enum in a constructor

From:
 smcardle@smcardle.com
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 21 Sep 2007 05:09:50 -0700
Message-ID:
<1190376590.000058.254800@k79g2000hse.googlegroups.com>
On Sep 20, 10:33 pm, Wojtek <nowh...@a.com> wrote:

Given the following:
---------------------------------
public class Foo
{
  private static final int DEFAULT_LENGTH = 30;
  private Type ivType;
  private int ivLength;

  public enum Type
  {
    OTHER,
    FIXED,
    VARIABLE;
  }

  public Foo(Type type)
  {
    this(type,DEFAULT_LENGTH);
  }

  public Foo(Type.VARIABLE varType, int length)
  {
    this(varType,length);
  }

  private Foo(Type type, int length)
  {
    super();
    ivType = type;
    ivLength = length;
  }}

---------------------------------

The compiler complains that Type.VARIABLE cannot be used. Obviously
what I want is that if the Type is VARIABLE, then I want the length in
the constructor, otherwise I will use the default length.

And yes I know I can have a constructor that only takes (int length)
and then assume that the Type is VARIABLE. That is not the point here.

--
Wojtek :-)


So what about this then

public class Foo
{
  private static final int DEFAULT_LENGTH = 30;
  private Type ivType;
  private int ivLength;

  public enum Type
  {
    OTHER,
    FIXED,
    VARIABLE;
  }

  public Foo(Type type)
  {
    this(type,DEFAULT_LENGTH);
  }

  public Foo(Type type, int length)
  {
      ivType = type;
      switch(type) {
      case VARIABLE:
          ivLength = DEFAULT_LENGTH;
          break;
      default:
          ivLength = length;

      }
  }
}

Steve

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