Re: Type safety ... References to generic type Enumeration<E> should be parameterized

From:
Hendrik Maryns <hendrik_maryns@despammed.com>
Newsgroups:
comp.lang.java.help
Date:
Wed, 30 Aug 2006 12:09:28 +0200
Message-ID:
<ed3o4o$8bj$1@newsserv.zdv.uni-tuebingen.de>
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Ian Wilson schreef:

In Eclipse, this code produces a warning at "foo.nextElement()" saying

"Type safety: The method nextElement() belongs to the raw type
Enumeration. References to generic type Enumeration<E> should be
parameterized"

    void listDefaults() {
        UIDefaults uiDefaults = UIManager.getDefaults();
        Enumeration foo = uiDefaults.keys();
        while (foo.hasMoreElements()) {
            Object key = foo.nextElement();
            Object val = uiDefaults.get(key);
            System.out.println("[" + key.toString() + "]:["
                    + (null != val ? val.toString() : "(null)") + "]");
        }
    }

How should I fix this?


By doing as it says:

Enumeration<Object> foo = uiDefaults.keys()

Or have a look at the API of UIDefaults, to see whether it is some more
specific Enumeration (I suppose not).

H.
- --
Hendrik Maryns

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