Re: Algorithms

From:
Chris Riesbeck <Chris.Riesbeck@gmail.com>
Newsgroups:
comp.lang.java.help
Date:
Thu, 29 Mar 2007 13:43:06 -0500
Message-ID:
<572flrF2brmhuU1@mid.individual.net>
Piotr Kobzda wrote:

Chris Smith wrote:

Patricia Shanahan <pats@acm.org> wrote:

There are design patterns for algorithms. Once you learn them, with a
bit of practice algorithm problems start feeling like
divide-and-conquer, or feeling like dynamic programming.


True, but in this case I get the feeling that the problem was more in
understanding the problem than in finding an algorithm. I get the
sense that the person who asked would have trouble answering basic
clarifying questions about the problem. The biggest is: if there are
multiple possible roman numerals for a given number, what criteria are
used to decide which one is desired? Without an answer to that, the
most clear and elegant algorithm is a simple greedy algorithm that
looks like this:

    String[] syms = { "C", "L", "X","V","I"}
    int[] vals = { 100, 50, 10, 5, 1 }

    ans = "";

    for (int i = 0; i < syms.length; i++)
    {
        while (value > vals[i])


Should be '>=' here.

        {
            ans += syms[i];
            value -= vals[i];
        }
    }

    return ans;

I suspect that most people will be unhappy with the result, but why?
The answer is a perfectly valid roman numeral.


Yes. And the algorithm is valid as well. It only lack some data for
the different requirements, e.g.:

    String[] syms = { "M",
"CM","D","CD","C","XC","L","XL","X","IX","V","IV","I" };
    int[] vals = { 1000,900, 500,400, 100,90, 50, 40, 10, 9, 5,
 4, 1 };

Until the requirements are nailed down in this way, it's too early to
think about algorithms.


Almost true -- your algorithm is the exception. ;)


Or, if you love writing code and hate writing data, and/or want to
handle old/new style numerals:

String[] syms = { "M", "D", "C", "L", "X", "V", "I" };
int[] vals = { 1000, 500, 100, 50, 10, 5, 1 };

   String ans = "";
   for (int i = 0; i < syms.length; i++) {
     while (n >= vals[i]) {
      ans += syms[i];
      n -= vals[i];
     }
     if (modern) {
       int k = i + 2 - i % 2;
       if ((k < syms.length) && (n >= vals[i] - vals[k])) {
         ans += syms[k] + syms[i];
         n -= vals[i] - vals[k];
       }
     }
   }

Personally, I prefer the data version, unless you need to handle old
style non-subtractive Roman numerals.

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