Re: Reverse sorting an array

From:
Fred <albert.xtheunknown0@gmail.com>
Newsgroups:
comp.lang.java.help
Date:
Fri, 30 Sep 2011 15:31:38 -0700 (PDT)
Message-ID:
<2b9bc8c9-d6de-431f-8753-fe9d400e9b1b@n36g2000yqb.googlegroups.com>
Eric Sosman wrote:

On 9/30/2011 7:03 AM, Fred wrote:
<snip>

import java.util.*;

class InputCounter {
     public static void main(String[] args) {
   final int MAX_NUMBERS = 50;
   int[] array = new int[MAX_NUMBERS];
   Arrays.sort(array, Collections.reverseOrder());
     }
}


     Because the Collections class has no .reverseOrder() method.
It has a .reverseOrder(Comparator) method: You feed it a Comparator
and it returns a new Comparator that inverts the sense of the one
you provided, but it has no method that manufactures a Comparator
out of thin air.

     But even if you get over that hurdle it won't do you any good.
A characteristic of Java (some call it a flaw) is that "primitives"
are not objects. In particular, an `int' is not an object: It has
no methods, you can't aim a reference at it, and so on. Among
other things, this means you cannot apply a Comparator to a pair
of `int's, because the Comparator's .compare(Object,Object) method
needs references to two objects. This is why the Arrays class has
distinct methods .sort(int[]), .sort(double[]), .sort(byte[]), and
so on, in addition to .sort(Object[]).

     What problem are you trying to solve?


I think the easiest way is to use sort() and then go through the array
from n-1 to 0.

<snip>

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