Re: Converting a HashMap<String, Thing> into a sorted array

From:
"Daniel Dyer" <"You don't need it">
Newsgroups:
comp.lang.java.programmer
Date:
Sat, 21 Oct 2006 17:33:14 +0100
Message-ID:
<op.thr5loqh8kxvgr@jack.local>
On Sat, 21 Oct 2006 16:25:18 +0100, qu0ll <qu0llSixFour@gmail.com> wrote=
:

I would like to code a method to convert a particular HashMap into a =

sorted
array. This is what I came up with:

public convert(final HashMap<String, Thing> things)
{
   Thing[] tArray = new Thing[things.size()];
   Collection<Thing> tCollection = things.values();
   int i = 0;
   for (Thing t : tCollection)
   {
      tArray[i++] = t;
   }
   Arrays.sort(tArray);
   return tArray;
}

Well it works but is there a more efficient/elegant way of doing this?=

Also, it would be nice to write it in such a way that it would convert=

  =

any
HashMap not just those using Thing. Can anyone assist?


There's a more concise way:

    public Thing[] convert(HashMap<String, Thing> things)
    {
        Thing[] tArray = things.values().toArray(new Thing[things.size()]=
);
        Arrays.sort(tArray);
        return tArray;
    }

You could use generics to write a version that will work with any Map (n=
ot =

just HashMap). The signature would look like this:

    public <T extends Comparable> T[] convert(Map<?, T> things)

However, generics and arrays don't mix very well so the implementation =

might be a little bit ugly. It's just about impossible to derive the =

correct type of T at runtime in this instance, so this might have to =

weakened to this:

    public Object[] convert(Map<?, ? extends Comparable> things)

Consider using Lists instead of arrays.

Dan.

-- =

Daniel Dyer
http://www.uncommons.org

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