Re: Problem executing an exe executable!
<mohsen_fakhari@yahoo.com> wrote in message
news:1163059154.833812.316100@e3g2000cwe.googlegroups.com...
Hello
I'm trying to run a exe file named butil.exe from within a java
application.
This is my code:
Process p = run.exec("d:\\modec160\\p_21\\butil.exe");
BufferedReader err =new BufferedReader(new
InputStreamReader(p.getErrorStream()));
BufferedReader in = new BufferedReader(new
InputStreamReader(p.getInputStream()));
String line;
while ((line = in.readLine()) != null) {
System.out.println(line);
}
while ((line = err.readLine()) != null) {
System.out.println(line);
}
int exitValue = p.waitFor();
System.out.println("Process exit value: " + exitValue);
exitValue is always 2.
Like many other programms 'butil' when run without any arguments will
give a usage discription,
but I don't have anything.
When I give its arguments,it should create a text file but I don't have
it too.
If it is important butil belongs to Btrieve,an old record manager and
I'm using JDK1.4 on winXP
Any thing you think may help,may really help.
Thank you.
Return code 2 on Windows means that the file 'd:\\modec160\\p_21\\butil.exe'
does not exist. Perhaps you've just mistyped the path? By the way, here's a
link to the full set of Windows return codes:
http://msdn.microsoft.com/library/?url=/library/en-us/debug/base/system_error_codes.asp?frame=true
Also, I found this article very useful in helping me with problems in
running executables:
http://www.javaworld.com/javaworld/jw-12-2000/jw-1229-traps_p.html.
--
Rhino
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